• POJ1741 点分治模板


    传送门:http://poj.org/problem?id=1741

    题意:

    求树上两点间路径长度小于k的点对个数

    题解:

    参考资料

    守望的淀粉质略解:https://www.luogu.org/blog/user9012/dian-fen-zhi-lve-xie

    粉红兔大佬的淀粉质:https://www.cnblogs.com/PinkRabbit/p/8593080.html

    算法步骤

    1. 计算重心位置
    2. 计算答案
    3. 分治子问题继续求解(1~3)

    代码:

    #include <set>
    #include <map>
    #include <cmath>
    #include <cstdio>
    #include <string>
    #include <vector>
    #include <cstring>
    #include <iostream>
    #include <algorithm>
    using namespace std;
    typedef long long LL;
    typedef pair<int, int> pii;
    typedef unsigned long long uLL;
    #define ls rt<<1
    #define rs rt<<1|1
    #define lson l,mid,rt<<1
    #define rson mid+1,r,rt<<1|1
    #define bug printf("*********
    ")
    #define FIN freopen("input.txt","r",stdin);
    #define FON freopen("output.txt","w+",stdout);
    #define IO ios::sync_with_stdio(false),cin.tie(0)
    #define debug1(x) cout<<"["<<#x<<" "<<(x)<<"]
    "
    #define debug2(x,y) cout<<"["<<#x<<" "<<(x)<<" "<<#y<<" "<<(y)<<"]
    "
    #define debug3(x,y,z) cout<<"["<<#x<<" "<<(x)<<" "<<#y<<" "<<(y)<<" "<<#z<<" "<<z<<"]
    "
    const int maxn = 3e5 + 5;
    const int INF = 0x3f3f3f3f;
    int n, k, Ans;
    
    struct EDGE {
        int v, nxt, w;
    } edge[maxn << 1];
    int head[maxn], tot;
    void add_edge(int u, int v, int w) {
        edge[tot].v = v;
        edge[tot].w = w;
        edge[tot].nxt = head[u];
        head[u] = tot++;
    }
    bool vis[10001];
    int Root, Tsiz, siz[10001], wt[10001];
    int arr[10001], cnt;
    
    void GetRoot(int u, int f) {
        siz[u] = 1; wt[u] = 0;
        for(int i = head[u]; i != -1; i = edge[i].nxt) {
            int v = edge[i].v;
            if(v != f && !vis[v]) {
                GetRoot(v, u);
                siz[u] += siz[v];
                wt[u] = max(wt[u], siz[v]);
            }
        }
        wt[u] = max(wt[u], Tsiz - siz[u]);
        if(wt[Root] > wt[u]) Root = u;
    }
    
    void Dfs(int u, int D, int f) {
        arr[++cnt] = D;
        for(int i = head[u]; i != -1; i = edge[i].nxt) {
            int v = edge[i].v;
            if(v != f && !vis[v]) {
                Dfs(v, D + edge[i].w, u);
            }
        }
    }
    
    int calc(int u, int D) {
        cnt = 0; Dfs(u, D, 0); int l = 1, r = cnt, sum = 0;
        sort(arr + 1, arr + cnt + 1);
        for(;; ++l) {
            while(r && arr[l] + arr[r] > k) --r;
            if(r < l) break;
            sum += r - l + 1;
        }
        return sum;
    }
    
    void DFS(int u) {
        Ans += calc(u, 0); vis[u] = 1;
        for(int i = head[u]; i != -1; i = edge[i].nxt) {
            int v = edge[i].v;
            if(!vis[v]) {
                Ans -= calc(v, edge[i].w);
                Root = 0, Tsiz = siz[v], GetRoot(v, 0);
                DFS(Root);
            }
        }
    }
    
    int main() {
    #ifndef ONLINE_JUDGE
        FIN
    #endif
        while(~scanf("%d%d", &n, &k) && n && k) {
            tot = Ans = 0;
            memset(vis, 0, sizeof(vis));
            memset(head, -1, sizeof(head));
            for(int i = 2, u, v, w; i <= n; i++) {
                scanf("%d%d%d", &u, &v, &w);
                add_edge(u, v, w);
                add_edge(v, u, w);
            }
            wt[0] = INF;
            Tsiz = n;
            GetRoot(1, 0);
            DFS(Root);
            printf("%d
    ", Ans - n);
        }
        return 0;
    }
    
    每一个不曾刷题的日子 都是对生命的辜负 从弱小到强大,需要一段时间的沉淀,就是现在了 ~buerdepepeqi
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  • 原文地址:https://www.cnblogs.com/buerdepepeqi/p/11172718.html
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