• hdu1134 Game of Connections 高精度 四则运算 模板


    即卡特兰数。

    #include <algorithm>
    #include <iostream>
    #include <cstring>
    #include <cstdio>
    #include <string>
    #include <stack>
    #include <cmath>
    #include <queue>
    #include <set>
    #include <map>
    #define FOR(i,s,t) for(int i = (s) ; i <= (t) ; ++i )
    
    typedef long long ll;
    typedef unsigned long long ull;
    using namespace std;
    
    const int inf=0x3f3f3f3f;
    const int maxn=1e6+5;
    
    /*
    * 高精度,支持四则运算和小于比较。
    */
    struct BigInt
    {
        const static int mod = 10000;
        const static int DLEN = 4;
        const static int MAXN=9999;
        int a[600],len;
        BigInt()
        {
            memset(a,0,sizeof(a));
            len = 1;
        }
        BigInt(int v)
        {
            memset(a,0,sizeof(a));
            len = 0;
            do
            {
                a[len++] = v%mod;
                v /= mod;
            }
            while(v);
        }
        BigInt(const char s[])
        {
            memset(a,0,sizeof(a));
            int L = strlen(s);
            len = L/DLEN;
            if(L%DLEN)len++;
            int index = 0;
            for(int i = L-1; i >= 0; i -= DLEN)
            {
                int t = 0;
                int k = i - DLEN + 1;
                if(k < 0)k = 0;
                for(int j = k; j <= i; j++)
                    t = t*10 + s[j] - '0';
                a[index++] = t;
            }
        }
        BigInt operator +(const BigInt &b)const
        {
            BigInt res;
            res.len = max(len,b.len);
            for(int i = 0; i <= res.len; i++)
                res.a[i] = 0;
            for(int i = 0; i < res.len; i++)
            {
                res.a[i] += ((i < len)?a[i]:0)+((i < b.len)?b.a[i]:0);
                res.a[i+1] += res.a[i]/mod;
                res.a[i] %= mod;
            }
            if(res.a[res.len] > 0)res.len++;
            return res;
        }
        BigInt operator -(const BigInt &b)const
        {
            int i,j,big;
            bool flag;
            BigInt t1,t2;
            if(b < *this)
            {
                t1=*this;
                t2=b;
                flag=0;
            }
            else
            {
                t1=b;
                t2=*this;
                flag=1;
            }
    
    
            big=t1.len;
            for(i=0; i<big; i++)
            {
                if(t1.a[i]<t2.a[i])
                {
                    j=i+1;
                    while(t1.a[j]==0)
                        j++;
                    t1.a[j--]--;
                    while(j>i)
                        t1.a[j--]+=MAXN;
                    t1.a[i]+=MAXN+1-t2.a[i];
                }
                else t1.a[i]-=t2.a[i];
            }
            t1.len=big;
            while(t1.a[len-1]==0 && t1.len>1)
            {
                t1.len--;
                big--;
            }
            if(flag)
                t1.a[big-1]=0-t1.a[big-1];
            return t1;
        }
    
    
        BigInt operator *(const BigInt &b)const
        {
            BigInt res;
            for(int i = 0; i < len; i++)
            {
                int up = 0;
                for(int j = 0; j < b.len; j++)
                {
                    int temp = a[i]*b.a[j] + res.a[i+j] + up;
                    res.a[i+j] = temp%mod;
                    up = temp/mod;
                }
                if(up != 0)
                    res.a[i + b.len] = up;
            }
            res.len = len + b.len;
            while(res.a[res.len - 1] == 0 &&res.len > 1)res.len--;
            return res;
        }
    
        BigInt operator /(const int &b)const
        {
            BigInt res;
            int i,down=0;
            for(i=len-1; i>=0; --i)
            {
                res.a[i]=(a[i]+down*(MAXN+1) )/b;
                down=a[i]+down*(MAXN+1)-res.a[i]*b;
            }
            res.len=len;
            while(res.a[res.len-1]==0 && res.len>1)res.len--;
            return res;
        }
    
        bool operator <(const BigInt&b)const
        {
            int ln;
            if( len < b.len )return true;
            else if( len==b.len )
            {
                ln=len-1;
                while(a[ln]==b.a[ln] && ln>=0 )ln--;
                if(ln>=0 && a[ln] < b.a[ln] )return true;
                else return false;
            }
            else return false;
        }
    
        void output()
        {
            printf("%d",a[len-1]);
            for(int i = len-2; i >=0 ; i--)
                printf("%04d",a[i]);
            printf("
    ");
        }
    };
    
    
    BigInt a[110];
    
    int main()
    {
        //freopen("in.txt","r",stdin);
        a[0]=BigInt(1);
        for(int i=1; i<=100; ++i)
        {
            a[i]=a[i-1]*( 4*i-2 )/(i+1);
        }
        int n;
        while(scanf("%d",&n)!=EOF)
        {
            if(n==-1)break;
            a[n].output();
        }
        return 0;
    }
    

      

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  • 原文地址:https://www.cnblogs.com/bruce27/p/4979152.html
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