RSA加密算法坑：pyasn1-error-when-reading-a-pem-string

开发只给了一串字符串，要转化成RSA加密的结果。

找了一堆rsa加密的算法：

# -*- coding: utf-8 -*-
import rsa
import base64

# 随机成一对密钥，然后保存.pem格式文件,也可以直接使用
(pubkey, privkey) = rsa.newkeys(2048)
pub = pubkey.save_pkcs1()
pubfile = open('public.pem', 'w+')
pubfile.write(str(pub, encoding="utf-8"))
pubfile.close()

pri = privkey.save_pkcs1()
prifile = open('private.pem', 'w+')
prifile.write(str(pri))
prifile.close()

message = 'abcdef'

with open('public.pem') as publickfile:
    p = publickfile.read()
    pubkey = rsa.PublicKey.load_pkcs1(p.encode(encoding='utf-8'))
with open('private.pem') as privatefile:
    p = privatefile.read()
    privkey = rsa.PrivateKey.load_pkcs1(p.encode(encoding='utf-8'))

# 公钥加密(为了展示可以用base64编码)
crypto = base64.b64encode(rsa.encrypt(message.encode(encoding='utf-8'), pubkey))
print("rsa加密结果:", crypto)
# 私钥解密
message = rsa.decrypt(base64.b64decode(crypto), privkey)
print("rsa解密结果:", message)

# sign 用私钥签名
signature = base64.b64encode(rsa.sign(message, privkey, 'SHA-1'))
print("加签结果:", signature)
# 再用公钥验证签名
res = rsa.verify(message, base64.b64decode(signature), pubkey)
print( "验签结果:",res)

将其中的一部分替换成了我自己的方法，生成了一个跟p一模一样的文件，怎么都不行，一直报错：

{PyAsn1Error}<TagSet object, tags 0:32:16> not in asn1Spec: <Integer schema object, tagSet <TagSet object, tags 0:0:2>>

import rsa
import base64
from pbkdf2 import xrange

s = 'MFwwDQYJKoZIhvcNAQEBBQADSwAwSAJBANkHLKYS2dByWQ3gKjQDvQbuWb/2Y9z4eYuLEfgXdiP5qc5cG/5c+c/GgIl6yQY7AYeZVXiBXLaGzxiLZ5Y4fi0CAwEAAQ=='
pubkey_str =('-----BEGIN RSA PUBLIC KEY-----'+'
' + '
'.join(s[pos:pos+64] for pos in xrange(0, len(s), 64)) + '
'+'-----END RSA PUBLIC KEY-----
')
pubkey_byte = pubkey_str.encode(encoding='utf-8')
pubkey = rsa.PublicKey.load_pkcs1(pubkey_byte)

报错解决办法查找到这个链接：

https://stackoverflow.com/questions/25243761/pyasn1-error-when-reading-a-pem-string

pyasn1-error-when-reading-a-pem-string

import rsa
pubkey = rsa.PublicKey.load_pkcs1_openssl_pem(b"""-----BEGIN PUBLIC KEY-----
MFwwDQYJKoZIhvcNAQEBBQADSwAwSAJBANkHLKYS2dByWQ3gKjQDvQbuWb/2Y9z4
eYuLEfgXdiP5qc5cG/5c+c/GgIl6yQY7AYeZVXiBXLaGzxiLZ5Y4fi0CAwEAAQ==
-----END PUBLIC KEY-----""")
crypto = rsa.encrypt(b"Secret", pubkey)

总算找到解决方案。。