• 函数附加练习1


    1、写两个函数,分别求两个整数的最大公约数和最小公倍数,用主函数调用这两个函数,并输出结果。两个整数由键盘输入。

    主要代码:

            static void Main(string[] args)
            {
                Program function = new Program();
                Console.Write("请输入:");
                double num1 = double.Parse(Console.ReadLine());
                Console.Write("请输入:");
                double num2 = double.Parse(Console.ReadLine());
                double num = function.divisor(num1, num2);
                double Num = function.multiple(num1, num2);
                Console.WriteLine("最大公约数为:{0},最小公倍数为:{1}。", num, Num);
                Console.ReadLine();
            }
            /// <summary>
            /// 最大公约数
            /// </summary>
            /// <param name="num1"></param>
            /// <param name="num2"></param>
            /// <returns></returns>
            public double divisor(double num1, double num2)
            {
                double temp = 0;
                double num = 0;
                if (num1 < num2)
                {
                    temp = num1;
                    num1 = num2;
                    num2 = temp;
                }
                while (num2 != 0)
                {
                    num = num1 % num2;
                    num1 = num2;
                    num2 = num;
                }
                return num1;
            }
            /// <summary>
            /// 最小公倍数
            /// </summary>
            /// <param name="num1"></param>
            /// <param name="num2"></param>
            /// <returns></returns>
            public double multiple(double num1, double num2)
            {
                double num = 0;
                Program method = new Program();
                double Num = method.divisor(num1, num2);
                num = num1 * num2 / Num;
                return num;
            }

    结果:

    2、求方程ax2+bx+c=0的根,用3个函数分别求当b2-4ac大于0、等于0和小于0时的根并输出,从主函数输入a,b,c的值。

    主要代码:

            static void Main(string[] args)
            {
                Program function = new Program();
                Console.Write("请输入a:");
                double a = double.Parse(Console.ReadLine());
                Console.Write("请输入b:");
                double b = double.Parse(Console.ReadLine());
                Console.Write("请输入c:");
                double c = double.Parse(Console.ReadLine());
                if (b * b - 4 * a * c > 0)
                {
                    double x1 = function.equation0(a, b, c);
                    double x2 = function.equation1(a, b, c);
                    Console.WriteLine("x1={0:f2},x2={1:f2}", x1, x2);
                }
                else if (b * b - 4 * a * c == 0)
                {
                    double x = function.equation2(a, b, c);
                    Console.WriteLine("x={0:f2}", x);
                }
                else
                    function.equation();
                Console.ReadLine();         
            }      
            /// <summary>
            /// 求一元二次方程,△>0
            /// </summary>
            /// <param name="a"></param>
            /// <param name="b"></param>
            /// <param name="c"></param>
            /// <returns></returns>
            public double equation0(double a, double b, double c)
            {
                double D = b * b - 4 * a * c;
                double x = (((-b) + Math.Sqrt(D)) / (2 * a));
                return x;
            }
            public double equation1(double a, double b, double c)
            {
                double D = b * b - 4 * a * c;
                double x = (((-b) - Math.Sqrt(D)) / (2 * a));
                return x;
            }
            /// <summary>
            /// 求一元二次方程,△=0
            /// </summary>
            /// <param name="a"></param>
            /// <param name="b"></param>
            /// <param name="c"></param>
            /// <returns></returns>
            public double equation2(double a, double b, double c)
            {
                double D = b * b - 4 * a * c;
                double x = (((-b) + Math.Sqrt(D)) / (2 * a));
                return x;
            }
            /// <summary>
            /// 求一元二次方程,△<0
            /// </summary>
            public void equation()
            {
                Console.WriteLine("此方程无实根!");
            }
            static void Main(string[] args)
            {
                //△>0的另一种写法。
                Program function = new Program();
                double x1;
                double x2;
                function.equation(out x1, out x2);
                Console.WriteLine("x1={0:f2},x2={1:f2}", x1, x2);
                Console.ReadLine();
            }
            public void equation(out double x1, out double x2)
            {
                Console.Write("请输入a:");
                double a = double.Parse(Console.ReadLine());
                Console.Write("请输入b:");
                double b = double.Parse(Console.ReadLine());
                Console.Write("请输入c:");
                double c = double.Parse(Console.ReadLine());
                double D = b * b - 4 * a * c;
                x1 = (((-b) + Math.Sqrt(D)) / (2 * a));
                x2 = (((-b) - Math.Sqrt(D)) / (2 * a));
            }

    结果:

    1)△>0

    2)△=0

    3)△<0

    3、写一个判断素数的函数,在主函数输入一个整数,输出是否为素数的信息。

    主要代码:

            static void Main(string[] args)
            {
                Program method = new Program();
                Console.Write("请输入:");
                int a = int.Parse(Console.ReadLine());
                method.number(a);
                Console.ReadLine();
            }
            public void number(int n)
            {
                int count = 0;
                for (int i = 1; i <= n; i++)
                {
                    if (n % i == 0)
                    {
                        count++;
                    }
                }
                if (count == 2)
                    Console.WriteLine("你输入的是素数!");
                else
                    Console.WriteLine("你输入的不是素数!");
            }

    结果:

    4、写一个函数,是给定的一个nxn的二维整形数组转置

    主要代码:

            static void Main(string[] args)
            {
                //法一
                Program method = new Program();
                Console.Write("请输入维数n:");
                int n = int.Parse(Console.ReadLine());
                double[,] m = new double[n, n];
                for (int i = 0; i < n; i++)
                {
                    for (int j = 0; j < n; j++)
                    {
                        Console.Write("请输入:");
                        m[i, j] = double.Parse(Console.ReadLine());
                    }
                }
                Console.WriteLine("原数组:");
                for (int i = 0; i < n; i++)
                {
                    for (int j = 0; j < n; j++)
                    {
                        Console.Write(m[i, j] + "	");
                    }
                    Console.WriteLine();
                }
                Console.WriteLine("转置数组:");
                method.array(m, n);
                Console.ReadLine();
            }
            public void array(double[,] m, double n)
            {
                double temp = 0;
                for (int i = 0; i < n; i++)
                {
                    for (int j = i + 1; j < n; j++)
                    {
                        temp = m[i, j];
                        m[i, j] = m[j, i];
                        m[j, i] = temp;
                    }
                }
                for (int i = 0; i < n; i++)
                {
                    for (int j = 0; j < n; j++)
                    {
                        Console.Write(m[i, j] + "	");
                    }
                    Console.WriteLine();
                }
            }
            static void Main(string[] args)
            {
                //法二
                Program method = new Program();
                Console.Write("请输入维数n:");
                int n = int.Parse(Console.ReadLine());
                double[,] m = new double[n, n];
                for (int i = 0; i < n; i++)
                {
                    for (int j = 0; j < n; j++)
                    {
                        Console.Write("请输入:");
                        m[i, j] = double.Parse(Console.ReadLine());
                    }
                }
                Console.WriteLine("原数组:");
                for (int i = 0; i < n; i++)
                {
                    for (int j = 0; j < n; j++)
                    {
                        Console.Write(m[i, j] + "	");
                    }
                    Console.WriteLine();
                }
                Console.WriteLine("转置数组:");
                double[,] m1 = method.array(m, n);
                for (int i = 0; i < n; i++)
                {
                    for (int j = 0; j < n; j++)
                    {
                        Console.Write(m1[i, j] + "	");
                    }
                    Console.WriteLine();
                }
                Console.ReadLine();
            }
            public double[,] array(double[,] m, int n)
            {
                double temp = 0;
                for (int i = 0; i < n; i++)
                {
                    for (int j = i + 1; j < n; j++)
                    {
                        temp = m[i, j];
                        m[i, j] = m[j, i];
                        m[j, i] = temp;
                    }
                }
                return m;
            }

    结果:

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  • 原文地址:https://www.cnblogs.com/bosamvs/p/5483299.html
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