居然是KD解。
1 /* 4347 */ 2 #include <iostream> 3 #include <sstream> 4 #include <string> 5 #include <map> 6 #include <queue> 7 #include <set> 8 #include <stack> 9 #include <vector> 10 #include <deque> 11 #include <algorithm> 12 #include <cstdio> 13 #include <cmath> 14 #include <ctime> 15 #include <cstring> 16 #include <climits> 17 #include <cctype> 18 #include <cassert> 19 #include <functional> 20 #include <iterator> 21 #include <iomanip> 22 using namespace std; 23 //#pragma comment(linker,"/STACK:102400000,1024000") 24 25 #define sti set<int> 26 #define stpii set<pair<int, int> > 27 #define mpii map<int,int> 28 #define vi vector<int> 29 #define pii pair<int,int> 30 #define vpii vector<pair<int,int> > 31 #define rep(i, a, n) for (int i=a;i<n;++i) 32 #define per(i, a, n) for (int i=n-1;i>=a;--i) 33 #define clr clear 34 #define pb push_back 35 #define mp make_pair 36 #define fir first 37 #define sec second 38 #define all(x) (x).begin(),(x).end() 39 #define SZ(x) ((int)(x).size()) 40 #define lson l, mid, rt<<1 41 #define rson mid+1, r, rt<<1|1 42 43 int id, n, m, K; 44 45 typedef struct node_t { 46 int x[5]; 47 48 friend bool operator< (const node_t& a, const node_t& b) { 49 return a.x[id] < b.x[id]; 50 } 51 52 double Distance(const node_t& a) { 53 __int64 ret = 0; 54 55 rep(i, 0, K) 56 ret += 1LL*(a.x[i]-x[i])*(a.x[i]-x[i]); 57 58 return ret; 59 } 60 61 void print() { 62 printf("%d", x[0]); 63 rep(i, 1, K) 64 printf(" %d", x[i]); 65 putchar(' '); 66 } 67 68 } node_t; 69 70 typedef struct Node { 71 __int64 d; 72 node_t p; 73 74 Node() {} 75 Node(__int64 d, node_t& p): 76 d(d), p(p) {} 77 78 friend bool operator< (const Node& a, const Node& b) { 79 return a.d < b.d; 80 } 81 82 } Node; 83 84 const int maxn = 50005; 85 node_t nd[maxn]; 86 vector<node_t> ans; 87 88 typedef struct KD_tree{ 89 static const int maxd = 5; 90 static const int maxn = 50005; 91 node_t P[maxn<<2]; 92 int idx[maxn<<2]; 93 priority_queue<Node> Q; 94 95 void Build(int deep, int l, int r, int rt) { 96 if (l > r) 97 return ; 98 idx[rt] = deep % K; 99 if (l == r) { 100 P[rt] = nd[l]; 101 return ; 102 } 103 104 id = idx[rt]; 105 int mid = (l + r) >> 1; 106 nth_element(nd+l, nd+mid, nd+r+1); 107 P[rt] = nd[mid]; 108 Build(deep+1, l, mid-1, rt<<1); 109 Build(deep+1, mid+1, r, rt<<1|1); 110 } 111 112 void Query(node_t x, int l, int r, int rt) { 113 if (l > r) 114 return ; 115 116 int id = idx[rt]; 117 __int64 tmp = x.Distance(P[rt]); 118 if (l == r) { 119 if (SZ(Q) < m) { 120 Q.push(Node(tmp, P[rt])); 121 } else { 122 if (tmp < Q.top().d) { 123 Q.pop(); 124 Q.push(Node(tmp, P[rt])); 125 } 126 } 127 return ; 128 } 129 130 int mid = (l + r) >> 1; 131 132 if (P[rt].x[id] >= x.x[id]) { 133 Query(x, l, mid-1, rt<<1); 134 if (SZ(Q) < m) { 135 Q.push(Node(tmp, P[rt])); 136 Query(x, mid+1, r, rt<<1|1); 137 } else { 138 if (tmp < Q.top().d) { 139 Q.pop(); 140 Q.push(Node(tmp, P[rt])); 141 } 142 if (1LL*(x.x[id]-P[rt].x[id])*(x.x[id]-P[rt].x[id]) < Q.top().d) { 143 Query(x, mid+1, r, rt<<1|1); 144 } 145 } 146 } else { 147 Query(x, mid+1, r, rt<<1|1); 148 if (SZ(Q) < m) { 149 Q.push(Node(tmp, P[rt])); 150 Query(x, l, mid-1, rt<<1); 151 } else { 152 if (tmp < Q.top().d) { 153 Q.pop(); 154 Q.push(Node(tmp, P[rt])); 155 } 156 if (1LL*(x.x[id]-P[rt].x[id])*(x.x[id]-P[rt].x[id]) < Q.top().d) { 157 Query(x, l, mid-1, rt<<1); 158 } 159 } 160 } 161 } 162 163 void Dump() { 164 ans.clr(); 165 while (!Q.empty()) { 166 ans.pb(Q.top().p); 167 Q.pop(); 168 } 169 } 170 } KD_tree; 171 172 KD_tree kd; 173 174 void solve() { 175 int q, sz; 176 node_t p; 177 178 kd.Build(0, 0, n-1, 1); 179 scanf("%d", &q); 180 while (q--) { 181 rep(j, 0, K) 182 scanf("%d", &p.x[j]); 183 scanf("%d", &m); 184 kd.Query(p, 0, n-1, 1); 185 kd.Dump(); 186 sz = SZ(ans); 187 printf("the closest %d points are: ", m); 188 per(i, 0, sz) { 189 ans[i].print(); 190 } 191 } 192 } 193 194 int main() { 195 ios::sync_with_stdio(false); 196 #ifndef ONLINE_JUDGE 197 freopen("data.in", "r", stdin); 198 freopen("data.out", "w", stdout); 199 #endif 200 201 while (scanf("%d %d", &n, &K)!=EOF) { 202 rep(i, 0, n) 203 rep(j, 0, K) 204 scanf("%d", &nd[i].x[j]); 205 solve(); 206 } 207 208 #ifndef ONLINE_JUDGE 209 printf("time = %d. ", (int)clock()); 210 #endif 211 212 return 0; 213 }
数据发生器。
1 from copy import deepcopy 2 from random import randint, shuffle 3 import shutil 4 import string 5 6 7 def GenDataIn(): 8 with open("data.in", "w") as fout: 9 t = 10 10 bound = 10**5 11 for tt in xrange(t): 12 n = randint(100, 200) 13 k = randint(1, 5) 14 fout.write("%d %d " % (n, k)) 15 for i in xrange(n): 16 L = [] 17 for j in xrange(k): 18 x = randint(-1000, 1000) 19 L.append(x) 20 fout.write(" ".join(map(str, L)) + " ") 21 q = randint(20, 30) 22 fout.write("%d " % (q)) 23 for qq in xrange(q): 24 L = [] 25 for j in xrange(k): 26 x = randint(-1000, 1000) 27 L.append(x) 28 fout.write(" ".join(map(str, L)) + " ") 29 m = randint(1, 10) 30 fout.write("%d " % (m)) 31 32 33 def MovDataIn(): 34 desFileName = "F:eclipse_prjworkspacehdojdata.in" 35 shutil.copyfile("data.in", desFileName) 36 37 38 if __name__ == "__main__": 39 GenDataIn() 40 MovDataIn()