• 【HDOJ】1540 Tunnel Warfare


    还不错的一道线段树区间合并。挺巧妙的用法。

      1 /* 1540 */
      2 #include <iostream>
      3 #include <string>
      4 #include <map>
      5 #include <queue>
      6 #include <set>
      7 #include <stack>
      8 #include <vector>
      9 #include <deque>
     10 #include <algorithm>
     11 #include <cstdio>
     12 #include <cmath>
     13 #include <ctime>
     14 #include <cstring>
     15 #include <climits>
     16 #include <cctype>
     17 #include <cassert>
     18 #include <functional>
     19 #include <iterator>
     20 #include <iomanip>
     21 using namespace std;
     22 //#pragma comment(linker,"/STACK:102400000,1024000")
     23 
     24 #define sti                set<int>
     25 #define stpii            set<pair<int, int> >
     26 #define mpii            map<int,int>
     27 #define vi                vector<int>
     28 #define pii                pair<int,int>
     29 #define vpii            vector<pair<int,int> >
     30 #define rep(i, a, n)     for (int i=a;i<n;++i)
     31 #define per(i, a, n)     for (int i=n-1;i>=a;--i)
     32 #define clr                clear
     33 #define pb                 push_back
     34 #define mp                 make_pair
     35 #define fir                first
     36 #define sec                second
     37 #define all(x)             (x).begin(),(x).end()
     38 #define SZ(x)             ((int)(x).size())
     39 #define lson            l, mid, rt<<1
     40 #define rson            mid+1, r, rt<<1|1
     41 
     42 const int maxn = 50005;
     43 int ls[maxn<<2], rs[maxn<<2], ms[maxn<<2];
     44 int S[maxn], top;
     45 
     46 void Build(int l, int r, int rt) {
     47     ls[rt] = rs[rt] = ms[rt] = r - l + 1;
     48     if (l == r)
     49         return ;
     50     
     51     int mid = (l + r) >> 1;
     52     Build(lson);
     53     Build(rson);
     54 }
     55 
     56 void PushUp(int l, int r, int rt) {
     57     int mid = (l + r) >>1;
     58     int lb = rt<<1;
     59     int rb = lb |1;
     60     
     61     ls[rt] = ls[lb];
     62     rs[rt] = rs[rb];
     63     if (ls[lb] == mid-l+1)
     64         ls[rt] += ls[rb];
     65     if (rs[rb] == r-mid)
     66         rs[rt] += rs[lb];
     67     
     68     ms[rt] = max(ms[lb], ms[rb]);
     69     ms[rt] = max(ms[rt], rs[lb]+ls[rb]);
     70 }
     71 
     72 void update(int x, int delta, int l, int r, int rt) {
     73     if (l == r) {
     74         ls[rt] = rs[rt] = ms[rt] = delta;
     75         return ;
     76     }
     77     
     78     int mid = (l + r) >> 1;
     79     
     80     if (x <= mid) {
     81         update(x, delta, lson);
     82     } else {
     83         update(x, delta, rson);
     84     }
     85     
     86     PushUp(l, r, rt);
     87 }
     88 
     89 int Query(int x, int l, int r, int rt) {
     90     if (l==r || ms[rt]==0 || ms[rt]==r-l+1)
     91         return ms[rt];
     92     
     93     int mid = (l + r) >> 1;
     94     int lb = rt<<1;
     95     int rb = lb |1;
     96     
     97     if (x <= mid) {
     98         if (x >= mid-rs[lb]+1) {
     99             return Query(x, lson) + Query(mid+1, rson);
    100         } else {
    101             return Query(x, lson);
    102         }
    103     } else {
    104         if (x <= mid+ls[rb]) {
    105             return Query(mid, lson) + Query(x, rson);
    106         } else {
    107             return Query(x, rson);
    108         }
    109     }
    110 }
    111 
    112 int main() {
    113     ios::sync_with_stdio(false);
    114     #ifndef ONLINE_JUDGE
    115         freopen("data.in", "r", stdin);
    116         freopen("data.out", "w", stdout);
    117     #endif
    118     
    119     int n, m, x;
    120     char cmd[5];
    121     int ans;
    122     
    123     while (scanf("%d %d", &n, &m)!=EOF) {
    124         Build(1, n, 1);
    125         top = 0;
    126         while (m--) {
    127             scanf("%s", cmd);
    128             if (cmd[0] == 'D') {
    129                 scanf("%d", &x);
    130                 S[top++] = x;
    131                 update(x, 0, 1, n, 1);
    132             } else if (cmd[0] == 'Q') {
    133                 scanf("%d", &x);
    134                 ans = Query(x, 1, n, 1);
    135                 printf("%d
    ", ans);
    136             } else {
    137                 if (top > 0) {
    138                     x = S[--top];
    139                     update(x, 1, 1, n, 1);
    140                 }
    141             }
    142         }
    143     }
    144     
    145     #ifndef ONLINE_JUDGE
    146         printf("time = %d.
    ", (int)clock());
    147     #endif
    148     
    149     return 0;
    150 }
  • 相关阅读:
    线程基础知识06 synchronized使用javap查看相关指令
    线程基础知识10volatile
    CSDN文章和博客园文章正确的转载方法
    记一次愚蠢的内存泄漏问题的排查
    常用五种排序方法 冒泡排序、快速排序、插入排序、希尔排序、归并排序
    virtualbox虚拟机使用
    itextsharp读取pdf时报错PdfReader not opened with owner password
    Python自动批量修改服务器密码
    Java设计模式——建造者模式
    Java设计模式——迭代器模式
  • 原文地址:https://www.cnblogs.com/bombe1013/p/4926454.html
Copyright © 2020-2023  润新知