A string S
of lowercase letters is given. We want to partition this string into as many parts as possible so that each letter appears in at most one part, and return a list of integers representing the size of these parts.
Example 1:
Input: S = "ababcbacadefegdehijhklij" Output: [9,7,8] Explanation: The partition is "ababcbaca", "defegde", "hijhklij". This is a partition so that each letter appears in at most one part. A partition like "ababcbacadefegde", "hijhklij" is incorrect, because it splits S into less parts.
Note:
S
will have length in range[1, 500]
.S
will consist of lowercase letters ('a'
to'z'
) only.
class Solution(object): def partitionLabels(self, S): """ :type S: str :rtype: List[int] """ #记录每个元素最后一次出现的位置 d = {c:i for i,c in enumerate(S)} res = [] start=end = 0 for i,c in enumerate(S): #设置尾部 end = max(end, d[c]) #当区间里所有元素都遍历过,设置下一个头部 if i == end: res.append(end-start+1) start = i+1 return res