Given two binary trees, write a function to check if they are the same or not.
Two binary trees are considered the same if they are structurally identical and the nodes have the same value.
Example 1:
Input: 1 1 / / 2 3 2 3 [1,2,3], [1,2,3] Output: true
Example 2:
Input: 1 1 / 2 2 [1,2], [1,null,2] Output: false
Example 3:
Input: 1 1 / / 2 1 1 2 [1,2,1], [1,1,2] Output: false
# Definition for a binary tree node. # class TreeNode(object): # def __init__(self, x): # self.val = x # self.left = None # self.right = None class Solution(object): def isSameTree(self, p, q): """ :type p: TreeNode :type q: TreeNode :rtype: bool """ if(p == None and q == None): return True if(p == None or q == None): return False if(p.val != q.val): return False return self.isSameTree(p.left, q.left) and self.isSameTree(p.right, q.right)