• HDU 1702 ACboy needs your help again!


    Problem Description
    ACboy was kidnapped!! 
    he miss his mother very much and is very scare now.You can't image how dark the room he was put into is, so poor :(.
    As a smart ACMer, you want to get ACboy out of the monster's labyrinth.But when you arrive at the gate of the maze, the monste say :" I have heard that you are very clever, but if can't solve my problems, you will die with ACboy."
    The problems of the monster is shown on the wall:
    Each problem's first line is a integer N(the number of commands), and a word "FIFO" or "FILO".(you are very happy because you know "FIFO" stands for "First In First Out", and "FILO" means "First In Last Out").
    and the following N lines, each line is "IN M" or "OUT", (M represent a integer).
    and the answer of a problem is a passowrd of a door, so if you want to rescue ACboy, answer the problem carefully!
     

    Input
    The input contains multiple test cases.
    The first line has one integer,represent the number oftest cases.
    And the input of each subproblem are described above.
     

    Output
    For each command "OUT", you should output a integer depend on the word is "FIFO" or "FILO", or a word "None" if you don't have any integer.
     

    Sample Input
    4 4 FIFO IN 1 IN 2 OUT OUT 4 FILO IN 1 IN 2 OUT OUT 5 FIFO IN 1 IN 2 OUT OUT OUT 5 FILO IN 1 IN 2 OUT IN 3 OUT
     

    Sample Output
    1 2 2 1 1 2 None 2 3
     
    再来一发STL,=.=,队列和栈都用用到
    #include<iostream>
    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    #include<limits.h>
    #include<queue>
    #include<stack>
    using namespace std;
    char c[10];
    int x;
    void solve_s(int n)
    {
        stack<int>s;
        while(n--)
        {
            scanf("%s",c);
            if(!strcmp(c,"IN"))
            {
                scanf("%d",&x);
                s.push(x);
            }
            else
            {
                if(!s.empty())
                {
                    printf("%d
    ",s.top());
                    s.pop();
                }
                else
                    printf("None
    ");
            }
        }
    }
    void solve_q(int n)
    {
        queue<int>q;
        while(n--)
        {
            scanf("%s",c);
            if(!strcmp(c,"IN"))
            {
                scanf("%d",&x);
                q.push(x);
            }
            else
            {
                if(!q.empty())
                {
                    printf("%d
    ",q.front());
                    q.pop();
                }
                else
                    printf("None
    ");
            }
        }
    }
    int main()
    {
        int t,n;
        char str[10];
        scanf("%d",&t);
        while(t--)
        {
            scanf("%d%s",&n,str);
            if(!strcmp(str,"FIFO"))
               solve_q(n);
            else
               solve_s(n);
        }
        return 0;
    }
    


  • 相关阅读:
    POJ 1182 食物链 并查集
    POJ 3666 Making the Grade DP
    POJ 1631 Bridging signals DP(最长上升子序列)
    POJ 1065 Wooden Sticks / hdu 1257 最少拦截系统 DP 贪心
    利用UUID 随机生成8位短号
    JS遍历子孙树
    前端中this的用法
    利用fetch进行POST传参
    SQL UNION 操作符
    Python 抖音机器人,论如何在抖音上找到漂亮小姐姐?
  • 原文地址:https://www.cnblogs.com/blfshiye/p/5412396.html
Copyright © 2020-2023  润新知