• LeetCode Merge Intervals


    Given a collection of intervals, merge all overlapping intervals.

    For example,
    Given [1,3],[2,6],[8,10],[15,18],
    return [1,6],[8,10],[15,18].

     1 /**
     2  * Definition for an interval.
     3  * public class Interval {
     4  *     int start;
     5  *     int end;
     6  *     Interval() { start = 0; end = 0; }
     7  *     Interval(int s, int e) { start = s; end = e; }
     8  * }
     9  */
    10  class intervalComparator implements Comparator<Interval>{
    11     @Override
    12     public int compare(Interval o1, Interval o2) {
    13         return o1.start-o2.start;
    14     }
    15 }
    16 public class Solution {
    17     public List<Interval> merge(List<Interval> intervals) {
    18         List<Interval> result = new ArrayList<Interval>();
    19         if (intervals.size() == 0) {
    20             return result;
    21         }
    22         Collections.sort(intervals, new intervalComparator());
    23         Interval first = intervals.get(0);
    24         Interval next;
    25         for (int i = 1; i <intervals.size() ; i++) {
    26             next = intervals.get(i);
    27             if (first.end < next.start) {
    28                 result.add(first);
    29                 first = next;
    30             } else {
    31                 if (first.end < next.end) {
    32                     first.end = next.end;
    33                 } 
    34             }
    35         }
    36         result.add(first);
    37         return result;
    38     }
    39 }
  • 相关阅读:
    opengl编程指南
    Binder机制1---Binder原理介绍
    [Android]使用platform密钥来给apk文件签名的命令
    IntentFilter
    最高分是多少
    Spring注入
    Bean容器的初始化
    Spring中的Junit
    IOC
    接口及面向接口编程
  • 原文地址:https://www.cnblogs.com/birdhack/p/4229898.html
Copyright © 2020-2023  润新知