Bitset
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 8457 Accepted Submission(s): 6552
Problem Description
Give you a number on base ten,you should output it on base two.(0 < n < 1000)
Input
For each case there is a postive number n on base ten, end of file.
Output
For each case output a number on base two.
Sample Input
1
2
3
Sample Output
1
10
11
Author
8600 && xhd
Source
Recommend
linle
解题:输出二进制数
#include <stdio.h> int main() { int b[11], n, i; while (~scanf("%d", &n)) { i = 0; while(n) { b[i++] = n % 2; n /= 2; } i--; while(i >= 0) printf("%d", b[i--]); printf(" "); } return 0; }