• Luogu2783 有机化学之神偶尔会做作弊 (树链剖分,缩点)


    当联通块size<=2时不管

    #include <iostream>
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    #include <cmath>
    #define R(a,b,c) for(register int  a = (b); a <= (c); ++ a)
    #define nR(a,b,c) for(register int  a = (b); a >= (c); -- a)
    #define Max(a,b) ((a) > (b) ? (a) : (b))
    #define Min(a,b) ((a) < (b) ? (a) : (b))
    #define Fill(a,b) memset(a, b, sizeof(a))
    #define Abs(a) ((a) < 0 ? -(a) : (a))
    #define Swap(a,b) a^=b^=a^=b
    #define ll long long
    
    #define ON_DEBUG
    
    #ifdef ON_DEBUG
    
    #define D_e_Line printf("
    
    ----------
    
    ")
    #define D_e(x)  cout << #x << " = " << x << endl
    #define Pause() system("pause")
    #define FileOpen() freopen("in.txt","r",stdin);
    
    #else
    
    #define D_e_Line ;
    #define D_e(x)  ;
    #define Pause() ;
    #define FileOpen() ;
    
    #endif
    
    struct ios{
        template<typename ATP>ios& operator >> (ATP &x){
            x = 0; int f = 1; char c;
            for(c = getchar(); c < '0' || c > '9'; c = getchar()) if(c == '-')  f = -1;
            while(c >= '0' && c <= '9') x = x * 10 + (c ^ '0'), c = getchar();
            x*= f;
            return *this;
        }
    }io;
    using namespace std;
    
    const int N = 10007;
    const int M = 50007;
    
    int n, m;
    struct Edge{
    	int nxt, pre, from;
    }e[M << 1], e2[M << 1];
    int head[N], head2[N], cntEdge, cntEdge2;
    inline void add(int u, int v){
    	e[++cntEdge] = (Edge){head[u], v, u}, head[u] = cntEdge;
    }
    inline void add2(int u, int v){
    	e2[++cntEdge2] = (Edge){head2[u], v}, head2[u] = cntEdge2; // !
    }
    
    namespace Tarjan{
    int dfn[N], dfnIndex, low[N], vis[N];
    int sta[N], top;
    int scc[N], sccIndex;
    inline void Tarjan(int u, int fa){
    	dfn[u] = low[u] = ++dfnIndex;
    	sta[++top] = u;
    	vis[u] = true;
    	for(register int i = head[u]; i; i = e[i].nxt){
    		int v = e[i].pre;
    		if(v == fa) continue; // size <= 2
    		if(!dfn[v]){
    			Tarjan(v, u);
    			low[u] = Min(low[u], low[v]);
    		}
    		else if(vis[v]){
    			low[u] = Min(low[u], dfn[v]);
    		}
    	}	
    	if(dfn[u] == low[u]){
    		++sccIndex;
    		do{
    			vis[sta[top]] = false;
    			scc[sta[top]] = sccIndex;
    		}while(sta[top--] != u); // !
    	}
    }
    inline void Rebuild(){
    	R(i,1,cntEdge){
    		if(scc[e[i].pre] != scc[e[i].from]){
    			add2(scc[e[i].from], scc[e[i].pre]); //!
    		}
    		
    	}
    }
    }
    
    namespace Tree{ // ! e, e2
    int dep[N], fa[N], son[N], siz[N];
    inline void DFS_First(int u, int father){
    	dep[u] = dep[father] + 1, fa[u] = father, siz[u] = 1;
    	for(register int i = head2[u]; i; i = e2[i].nxt){
    		int v = e2[i].pre;
    		if(v == father) continue;
    		DFS_First(v, u);
    		siz[u] += siz[v];
    		if(!son[u] || siz[v] > siz[son[u]]){
    			son[u] = v;
    		}
    	}
    }
    int dfn[N], dfnIndex, top[N];
    inline void DFS_Second(int u, int ancester){
    	dfn[u] = ++dfnIndex, top[u] = ancester;
    	if(!son[u]) return;
    	DFS_Second(son[u], ancester);
    	for(register int i = head2[u]; i; i = e2[i].nxt){
    		int v = e2[i].pre;
    		if(v != son[u] && v != fa[u]){
    			DFS_Second(v, v);
    		}
    	}
    }
    inline int Query(int x, int y){
    	int sum = 0;
    	while(top[x] != top[y]){
    		if(dep[top[x]] < dep[top[y]]) Swap(x, y);
    		sum += dep[x] - dep[top[x]] + 1;
    		x = fa[top[x]];
    	}
    	if(dep[x] < dep[y]) Swap(x, y);
    	return sum + dep[x] - dep[y] + 1;
    }
    }
    
    inline string Calc(int x){
    	string ans = "";
    	while(x){
    		ans += (x & 1) ? "1" : "0";
    		x >>= 1;
    	}
    	return ans;
    }
    int main(){
    	io >> n >> m;
    	R(i,1,m){
    		int u, v;
    		io >> u >> v;
    		add(u, v);
    		add(v, u);
    	}
    	
    	R(i,1,n){
    		if(!Tarjan::dfn[i]){
    			Tarjan::Tarjan(i ,0);
    		}
    	}
    	
    	Tarjan::Rebuild();
    	
    	Tree::DFS_First(1, 0);
    	Tree::DFS_Second(1, 1);
    	
    	int Ques;
    	io >> Ques;
    	while(Ques--){
    		int x, y;
    		io >> x >> y;
    		string ans = Calc(Tree::Query(Tarjan::scc[x], Tarjan::scc[y]));
    		int len = ans.size();
    		nR(i,len - 1, 0){
    			cout << ans[i];
    		}
    		putchar('
    ');
    	}
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/bingoyes/p/11275211.html
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