• Luogu3435 [POI2006]OKR-Periods of Words (KMP)


    (next)应用,将原串视作最长前缀复制后的子串

    #include <iostream>
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    #include <cmath>
    #define R(a,b,c) for(register int  a = (b); a <= (c); ++ a)
    #define nR(a,b,c) for(register int  a = (b); a >= (c); -- a)
    #define Max(a,b) ((a) > (b) ? (a) : (b))
    #define Min(a,b) ((a) < (b) ? (a) : (b))
    #define Fill(a,b) memset(a, b, sizeof(a))
    #define Abs(a) ((a) < 0 ? -(a) : (a))
    #define Swap(a,b) a^=b^=a^=b
    #define ll long long
    
    #define ON_DEBUG
    
    #ifdef ON_DEBUG
    
    #define D_e_Line printf("
    
    ----------
    
    ")
    #define D_e(x)  cout << #x << " = " << x << endl
    #define Pause() system("pause")
    #define FileOpen() freopen("in.txt","r",stdin);
    
    #else
    
    #define D_e_Line ;
    #define D_e(x)  ;
    #define Pause() ;
    #define FileOpen() ;
    
    #endif
    
    struct ios{
        template<typename ATP>ios& operator >> (ATP &x){
            x = 0; int f = 1; char c;
            for(c = getchar(); c < '0' || c > '9'; c = getchar()) if(c == '-')  f = -1;
            while(c >= '0' && c <= '9') x = x * 10 + (c ^ '0'), c = getchar();
            x*= f;
            return *this;
        }
    }io;
    using namespace std;
    
    int nxt[1000007];
    char str[1000007];
    int main(){
    	int len;
    	io >> len;
    	scanf("%s", str);
    	long long ans = 0;
    	int i = 0, j = -1;
    	nxt[0] = -1;
    	while(i < len){
    		if(j == -1 || str[i] == str[j]){
    			nxt[++i] = ++j;
    			while(nxt[nxt[i]] > 0) nxt[i] = nxt[nxt[i]];
    			if(nxt[i] > 0){
    				ans += i -nxt[i];
    			}
    		}
    		else
    			j = nxt[j];
    	}
    	
    	printf("%lld", ans);
    	return 0;
    } 
    

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  • 原文地址:https://www.cnblogs.com/bingoyes/p/11238883.html
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