• Luogu2439 [SDOI2005]阶梯教室设备利用 (动态规划)


    同上一题,区间改左闭右开就双倍经验了。貌似可以跑最长路。

    #include <iostream>
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    #include <cmath>
    #define R(a,b,c) for(register int  a = (b); a <= (c); ++ a)
    #define nR(a,b,c) for(register int  a = (b); a >= (c); -- a)
    #define Max(a,b) ((a) > (b) ? (a) : (b))
    #define Min(a,b) ((a) < (b) ? (a) : (b))
    #define Fill(a,b) memset(a, b, sizeof(a))
    #define Abs(a) ((a) < 0 ? -(a) : (a))
    #define Swap(a,b) a^=b^=a^=b
    #define ll long long
    
    #define ON_DEBUG
    
    #ifdef ON_DEBUG
    
    #define D_e_Line printf("
    
    ----------
    
    ")
    #define D_e(x)  cout << #x << " = " << x << endl
    #define Pause() system("pause")
    #define FileOpen() freopen("in.txt","r",stdin);
    
    #else
    
    #define D_e_Line ;
    #define D_e(x)  ;
    #define Pause() ;
    #define FileOpen() ;
    
    #endif
    
    struct ios{
        template<typename ATP>ios& operator >> (ATP &x){
            x = 0; int f = 1; char c;
            for(c = getchar(); c < '0' || c > '9'; c = getchar()) if(c == '-')  f = -1;
            while(c >= '0' && c <= '9') x = x * 10 + (c ^ '0'), c = getchar();
            x*= f;
            return *this;
        }
    }io;
    using namespace std;
    
    const int N = 10007;
    
    struct Field{
    	int l, r, w;
    	bool operator < (const Field &com) const{
    		if(r != com.r) return r < com.r;
    		return l < com.l;
    	}
    }a[N];
    
    int f[N];
    
    inline int Find(int x){
    	int l = 1, r = x;
    	int ans = -1;
    	while(l <= r){
    		int mid = (l + r) >> 1;
    		if(a[mid].r < a[x].l){
    			l = mid + 1;
    			ans = mid;
    		}
    		else{
    			r = mid - 1;
    		}
    	}
    	return ans;
    }
    int main(){
    	//FileOpen();
    	int n;
    	io >> n;
        R(i,1,n){
        	io >> a[i].l >> a[i].r;
        	--a[i].r;
        	a[i].w = a[i].r - a[i].l + 1;
        }
    
        sort(a + 1, a + n + 1);
        
        f[1] = a[1].w;
        R(i,2,n){
            int j = Find(i);
            if(j != -1)
            	f[i] = Max(f[i - 1], f[j] + a[i].w);
            else
            	f[i] = Max(f[i - 1], a[i].w);
        }
        
        printf("%d
    ",f[n]);
        
        return 0;
    }
    

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  • 原文地址:https://www.cnblogs.com/bingoyes/p/11221389.html
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