穷举法:
#include<iostream>
using namespace std;
unsigned long GCD(unsigned long a, unsigned long b)
{
if(a == 0)
return b;
else if(b == 0)
return a;
else if(a == b)
return a;
unsigned long gcd;
gcd = a>b?b:a;
while(gcd > 1)
{
if((a%gcd==0) && (b%gcd==0))
return gcd;
gcd--;
}
return gcd;
}
void main()
{
unsigned long a,b;
cout<<"请输入a 和b:>";
cin>>a>>b;
unsigned long gcd = GCD(a,b);
cout<<"gcd = "<<gcd<<endl;
}
相减法:
unsigned long gcd;
while(a!=b) { gcd = a>b?(a-=b):(b-=a); } return gcd;
相除法:
unsigned long mod = a%b; while(mod != 0) { a = b; b = mod; mod = a%b; }
递归:
unsigned long GCD(unsigned long a, unsigned long b) { if(b == 0) return a; else return GCD(b, a%b); }