Given a binary tree, flatten it to a linked list in-place.
For example, given the following tree:
1
/
2 5
/
3 4 6
The flattened tree should look like:
1
2
3
4
5
6
# Definition for a binary tree node.
class TreeNode:
def __init__(self, x):
self.val = x
self.left = None
self.right = None
class Solution:
def flatten(self, root):
"""
:type root: TreeNode
:rtype: void Do not return anything, modify root in-place instead.
"""
if root is None:
return
while root:
if root.left:
temp = root.left
while temp.right:
temp = temp.right
temp.right = root.right
root.right = root.left
root.left = None
root = root.right