• 2. Add Two Numbers


    You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

    You may assume the two numbers do not contain any leading zero, except the number 0 itself.

    Example:

    Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
    Output: 7 -> 0 -> 8
    Explanation: 342 + 465 = 807.
    


    class Solution:
        def addTwoNumbers(self, l1, l2):
            """
            :type l1: ListNode
            :type l2: ListNode
            :rtype: ListNode
            """
            if l1 is None:
                return l1
            elif l2 is None:
                return l1
            start = ListNode(0)
            temp = start
            carry = 0
            while l1 or l2:
                sum = 0
                if l1:
                    sum += l1.val
                    l1 = l1.next
                if l2:
                    sum += l2.val
                    l2 = l2.next
                sum += carry
                carry = 1 if sum>9 else 0
                temp.next = ListNode(sum % 10)
                temp = temp.next
            if carry:
                temp.next = ListNode(1)
            temp = start.next
            del start
            return temp

    链表题目,发现已经忘记怎么用链表了。。这道题用头结点会简单很多

    ps.说来惭愧,很久没有刷过题了,再忙也不应该成为不刷题的借口,于是从今日立下flag,每天刷五道题。

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  • 原文地址:https://www.cnblogs.com/bernieloveslife/p/9699838.html
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