Suppose you have a long flowerbed in which some of the plots are planted and some are not. However, flowers cannot be planted in adjacent plots - they would compete for water and both would die.
Given a flowerbed (represented as an array containing 0 and 1, where 0 means empty and 1 means not empty), and a number n, return if n new flowers can be planted in it without violating the no-adjacent-flowers rule.
Example 1:
Input: flowerbed = [1,0,0,0,1], n = 1 Output: True
Example 2:
Input: flowerbed = [1,0,0,0,1], n = 2 Output: False
Note:
- The input array won't violate no-adjacent-flowers rule.
- The input array size is in the range of [1, 20000].
- n is a non-negative integer which won't exceed the input array size.
class Solution(object): def canPlaceFlowers(self, flowerbed, n): """ :type flowerbed: List[int] :type n: int :rtype: bool """ l = len(flowerbed) if(l==1): if((flowerbed[0]==0 and n==1) or n==0): return True else: return False if(flowerbed[0]==0 and flowerbed[1]==0): flowerbed[0]=1 n -= 1 if(flowerbed[l-1]==0 and flowerbed[l-2]==0): flowerbed[l-1]=1 n -= 1 for i in range(1,l-2): if(flowerbed[i]==0 and flowerbed[i-1]==0 and flowerbed[i+1]==0): flowerbed[i]=1 n -= 1 if n<=0: return True else: return False