• 递归问题


    问题:

    Consider a three-parameter recursive function w(a, b, c):

    if a <= 0 or b <= 0 or c <= 0, then w(a, b, c) returns:
    1

    if a > 20 or b > 20 or c > 20, then w(a, b, c) returns:
    w(20, 20, 20)

    if a < b and b < c, then w(a, b, c) returns:
    w(a, b, c-1) + w(a, b-1, c-1) - w(a, b-1, c)

    otherwise it returns:
    w(a-1, b, c) + w(a-1, b-1, c) + w(a-1, b, c-1) - w(a-1, b-1, c-1)

    This is an easy function to implement. The problem is, if implemented directly, for moderate values of a, b and c (for example, a = 15, b = 15, c = 15), the program takes hours to run because of the massive recursion.

    Input
    The input for your program will be a series of integer triples, one per line, until the end-of-file flag of -1 -1 -1. Using the above technique, you are to calculate w(a, b, c) efficiently and print the result.

    Output
    Print the value for w(a,b,c) for each triple.

    Sample Input

    1 1 1 2 2 2 10 4 6 50 50 50 -1 7 18 -1 -1 -1

    Sample Output

    w(1, 1, 1) = 2 w(2, 2, 2) = 4 w(10, 4, 6) = 523 w(50, 50, 50) = 1048576 w(-1, 7, 18) = 1

    回答:典型的记忆化递归问题

        #include <stdio.h>  
        #include <limits.h>  
          
        const int MAX_N = 21;  
        int W[MAX_N][MAX_N][MAX_N];  
          
        int getValue(int a, int b, int c)  
        {  
            if (a <= 0 || b <= 0 || c <= 0) return W[0][0][0] = 1;  
            if (a >= MAX_N || b >= MAX_N || c >= MAX_N)  
                return getValue(MAX_N-1, MAX_N-1, MAX_N-1);  
          
            if (W[a][b][c]) return W[a][b][c];  
          
            if (a < b && b < c)  
            {  
                W[a][b-1][c-1] = getValue(a, b-1, c-1);  
                W[a][b][c-1] = getValue(a, b, c-1);  
                W[a][b-1][c] = getValue(a, b-1, c);  
                return W[a][b][c] = W[a][b][c-1] + W[a][b-1][c-1] - W[a][b-1][c];  
            }  
          
            W[a-1][b-1][c-1] = getValue(a-1, b-1, c-1);  
            W[a-1][b-1][c] = getValue(a-1, b-1, c);  
            W[a-1][b][c-1] = getValue(a-1, b, c-1);  
            W[a-1][b][c] = getValue(a-1, b, c);  
          
            return W[a][b][c] = W[a-1][b][c] + W[a-1][b-1][c]  
            + W[a-1][b][c-1] - W[a-1][b-1][c-1];  
        }  
          
        int main()  
        {  
            int a, b, c;  
            while (~scanf("%d %d %d", &a, &b, &c)&& !(a == -1 && b == -1 && c == -1))  
            {  
                printf("w(%d, %d, %d) = %d ", a, b, c, getValue(a, b, c));  
            }  
            return 0;  
        }

  • 相关阅读:
    A program file was not specified in the launch configuration.
    Effective C++条款38: 决不要重新定义继承而来的缺省参数值
    进程控制块
    Effective C++条款37: 决不要重新定义继承而来的非虚函数
    Effective C++条款42: 明智地使用私有继承
    迭代的是人,递归的是神(第一篇——递归调用的分析)
    Effective C++条款36: 区分接口继承和实现继承
    进程上下文
    进程的层次结构 ——进程组捕捉信号
    SQL语句的并集UNION,交集JOIN(内连接,外连接),交叉连接(CROSS JOIN笛卡尔积),差集(NOT IN)
  • 原文地址:https://www.cnblogs.com/benchao/p/4496554.html
Copyright © 2020-2023  润新知