• MySQL练习题及答案(复习)


    新建一个叫做 review 的数据库,将测试数据脚本导进去。(可以使用Navicat查询功能)

    /*
    Navicat MySQL Data Transfer
    
    Source Server         : DB
    Source Server Version : 50723
    Source Host           : localhost:3306
    Source Database       : review
    
    Target Server Type    : MYSQL
    Target Server Version : 50723
    File Encoding         : 65001
    
    Date: 2019-02-25 23:48:25
    */
    
    SET FOREIGN_KEY_CHECKS=0;
    
    -- ----------------------------
    -- Table structure for class
    -- ----------------------------
    DROP TABLE IF EXISTS `class`;
    CREATE TABLE `class` (
      `id` int(11) NOT NULL AUTO_INCREMENT,
      `name` char(4) DEFAULT NULL,
      PRIMARY KEY (`id`)
    ) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=utf8;
    
    -- ----------------------------
    -- Records of class
    -- ----------------------------
    INSERT INTO `class` VALUES ('1', '高三1班');
    INSERT INTO `class` VALUES ('2', '高三2班');
    INSERT INTO `class` VALUES ('3', '高三3班');
    
    -- ----------------------------
    -- Table structure for course
    -- ----------------------------
    DROP TABLE IF EXISTS `course`;
    CREATE TABLE `course` (
      `id` int(11) NOT NULL AUTO_INCREMENT,
      `name` char(8) NOT NULL,
      `teacher_id` int(11) DEFAULT NULL,
      PRIMARY KEY (`id`),
      UNIQUE KEY `name` (`name`),
      KEY `fk_cou_tea` (`teacher_id`),
      CONSTRAINT `fk_cou_tea` FOREIGN KEY (`teacher_id`) REFERENCES `teacher` (`id`)
    ) ENGINE=InnoDB AUTO_INCREMENT=5 DEFAULT CHARSET=utf8;
    
    -- ----------------------------
    -- Records of course
    -- ----------------------------
    INSERT INTO `course` VALUES ('1', 'python', '1');
    INSERT INTO `course` VALUES ('2', 'java', '2');
    INSERT INTO `course` VALUES ('3', 'php', '3');
    INSERT INTO `course` VALUES ('4', 'c', '1');
    
    -- ----------------------------
    -- Table structure for score
    -- ----------------------------
    DROP TABLE IF EXISTS `score`;
    CREATE TABLE `score` (
      `id` int(11) NOT NULL AUTO_INCREMENT,
      `student_id` int(11) DEFAULT NULL,
      `course_id` int(11) DEFAULT NULL,
      `mark` int(11) DEFAULT NULL,
      PRIMARY KEY (`id`),
      KEY `fk_sco_stu` (`student_id`),
      KEY `fk_sco_cou` (`course_id`),
      CONSTRAINT `fk_sco_cou` FOREIGN KEY (`course_id`) REFERENCES `course` (`id`),
      CONSTRAINT `fk_sco_stu` FOREIGN KEY (`student_id`) REFERENCES `student` (`id`)
    ) ENGINE=InnoDB AUTO_INCREMENT=18 DEFAULT CHARSET=utf8;
    
    -- ----------------------------
    -- Records of score
    -- ----------------------------
    INSERT INTO `score` VALUES ('1', '1', '2', '79');
    INSERT INTO `score` VALUES ('2', '2', '1', '58');
    INSERT INTO `score` VALUES ('3', '2', '3', '66');
    INSERT INTO `score` VALUES ('4', '2', '4', '80');
    INSERT INTO `score` VALUES ('5', '3', '1', '63');
    INSERT INTO `score` VALUES ('6', '3', '4', '95');
    INSERT INTO `score` VALUES ('7', '4', '2', '88');
    INSERT INTO `score` VALUES ('8', '4', '3', '62');
    INSERT INTO `score` VALUES ('9', '5', '2', '59');
    INSERT INTO `score` VALUES ('10', '5', '4', '100');
    INSERT INTO `score` VALUES ('11', '1', '1', '55');
    INSERT INTO `score` VALUES ('12', '3', '2', '81');
    INSERT INTO `score` VALUES ('13', '4', '4', '50');
    INSERT INTO `score` VALUES ('14', '5', '3', '77');
    INSERT INTO `score` VALUES ('15', '1', '4', '58');
    INSERT INTO `score` VALUES ('16', '1', '3', '91');
    INSERT INTO `score` VALUES ('17', '6', '2', '75');
    
    -- ----------------------------
    -- Table structure for student
    -- ----------------------------
    DROP TABLE IF EXISTS `student`;
    CREATE TABLE `student` (
      `id` int(11) NOT NULL AUTO_INCREMENT,
      `name` char(2) NOT NULL,
      `gender` char(1) DEFAULT NULL,
      `class_id` int(11) DEFAULT NULL,
      PRIMARY KEY (`id`),
      KEY `fk_cou_cla` (`class_id`),
      CONSTRAINT `fk_cou_cla` FOREIGN KEY (`class_id`) REFERENCES `class` (`id`)
    ) ENGINE=InnoDB AUTO_INCREMENT=7 DEFAULT CHARSET=utf8;
    
    -- ----------------------------
    -- Records of student
    -- ----------------------------
    INSERT INTO `student` VALUES ('1', '德玛', '', '1');
    INSERT INTO `student` VALUES ('2', '妖姬', '', '2');
    INSERT INTO `student` VALUES ('3', '盲僧', '', '3');
    INSERT INTO `student` VALUES ('4', '蜘蛛', '', '1');
    INSERT INTO `student` VALUES ('5', '卡牌', '', '2');
    INSERT INTO `student` VALUES ('6', '露露', '', '3');
    
    -- ----------------------------
    -- Table structure for teacher
    -- ----------------------------
    DROP TABLE IF EXISTS `teacher`;
    CREATE TABLE `teacher` (
      `id` int(11) NOT NULL AUTO_INCREMENT,
      `name` char(2) NOT NULL,
      PRIMARY KEY (`id`)
    ) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=utf8;
    
    -- ----------------------------
    -- Records of teacher
    -- ----------------------------
    INSERT INTO `teacher` VALUES ('1', '佩奇');
    INSERT INTO `teacher` VALUES ('2', '大熊');
    INSERT INTO `teacher` VALUES ('3', '路飞');
    测试数据脚本

    数据表结构如下图:

    练习题及答案如下:

    -- 1、查询所有的课程的名称以及对应的任课老师姓名
    select course.name as "课程",teacher.name as "任课老师" from course 
    left join
    teacher
    on
    course.teacher_id=teacher.id;
    
    ------------------------------------------------------------
    -- 2、查询学习课程"python"比课程"java"成绩低的学生的学号
    select python.student_id from
    (select score.student_id,course.name,score.mark from score inner join course on score.course_id=course.id where course.name="python") as python
    inner JOIN
    (select score.student_id,course.name,score.mark from score inner join course on score.course_id=course.id where course.name="java") as java
    on python.student_id=java.student_id
    where python.mark<java.mark;
    
    ------------------------------------------------------------
    -- 3、查询平均成绩大于65分的同学的id和平均成绩(保留两位小数)
    select student_id,round(avg(mark),2) as m from score
    group by student_id having m>65;
    
    ------------------------------------------------------------
    -- 4、查询平均成绩大于65分的同学的姓名和平均成绩(保留两位小数);
    select student.name,round(avg(mark),2) as m from score
    inner join
    student
    on
    score.student_id=student.id
    group by student_id having m>65;
    
    ------------------------------------------------------------
    -- 5、查询所有同学的姓名、选课数、总成绩
    select student.name,count(score.course_id) as "选课数",sum(score.mark) as "总成绩" from score 
    inner join
    student
    on
    score.student_id=student.id
    group by student_id;
    
    ------------------------------------------------------------
    -- 6、查询没学过"路飞"老师课的同学的姓名
    # 1)"路飞"老师任课的课程id
    select course.id from course inner join teacher on course.teacher_id=teacher.id where teacher.name="路飞"
    # 2)学过"路飞"老师的课的学生id
    select score.student_id from score where score.course_id in
    (select course.id from course inner join teacher on course.teacher_id=teacher.id where teacher.name="路飞")
    group by score.student_id
    # 3)最终结果
    select student.name from student where id not in
    (select score.student_id from score where score.course_id in
    (select course.id from course inner join teacher on course.teacher_id=teacher.id where teacher.name="路飞")
    group by score.student_id);
    
    ------------------------------------------------------------
    -- 7、查询学过"python"并且也学过"java"课程的同学的姓名
    select student.name from score 
    left join student on score.student_id=student.id
    where
    score.course_id=(select id from course where name="python")
    or
    score.course_id=(select id from course where name="java")
    group by score.student_id having count(1)>1;
    
    ------------------------------------------------------------
    -- 8、查询学过"路飞"老师所教的全部课程的同学的姓名
    select student.name from score inner join student on score.student_id=student.id where score.course_id in
    (select course.id from course inner join teacher on course.teacher_id=teacher.id where teacher.name="路飞")
    group by score.student_id;
    
    -- 9、查询有课程成绩小于60分的同学的姓名
    select name from student where id in
    (select student_id from score where mark<60 group by student_id);
    
    ------------------------------------------------------------
    -- 10、查询挂科超过两门(包括两门)的学生姓名
    select name from student where id in
    (select student_id from score where mark<60 group by student_id having count(1)>=2);
    ------------------------------------------------------------
    -- 11、查询选修了全部课程的学生姓名
    select name from student where id in
    (select student_id from score group by student_id having count(1)=(select count(1) from course));
    
    ------------------------------------------------------------
    -- 12、查询至少有一门课程与"卡牌"同学所学课程相同的同学姓名
    select name from student where id in
    (select student_id from score where course_id in
    (select course_id from score inner join student on score.student_id=student.id where student.name="卡牌")
    group by student_id)
    and name!="卡牌";
    
    ------------------------------------------------------------
    -- 13、查询学过"蜘蛛"同学全部课程的其他同学姓名
    # 1)"蜘蛛"同学学过的课程id
    select course_id from score inner join student on score.student_id=student.id where student.name="蜘蛛"
    # 2)score表连student表,并筛选出课程id在("蜘蛛"同学学过的课程id),并且学生!="蜘蛛"
    select student.name from score inner join student on score.student_id=student.id where score.course_id
    in (select course_id from score inner join student on score.student_id=student.id where student.name="蜘蛛")
    and student.name!="蜘蛛"
    # 3)接着对结果进行分组,再次筛选得到最终结果
    select student.name from score inner join student on score.student_id=student.id where score.course_id
    in (select course_id from score inner join student on score.student_id=student.id where student.name="蜘蛛")
    and student.name!="蜘蛛"
    group by student_id
    having count(1)=(select count(1) from score inner join student on score.student_id=student.id where student.name="蜘蛛");
    
    ------------------------------------------------------------
    -- 14、查询和"蜘蛛"同学学习的课程完全相同的其他同学姓名;
    # 1)找出与"蜘蛛"学习课程数相同的学生id(你学两门,我也学两门)
    select * from score where score.student_id 
    in
    (select student_id from score 
    group by score.student_id 
    having count(1)=(select count(1) from score inner join student on score.student_id=student.id where student.name="蜘蛛"))
    # 2)找出学过"蜘蛛"课程的学生,剩下的一定是至少学过一门"蜘蛛"课程的学生
    select * from score where score.student_id 
    in
    (select student_id from score 
    group by score.student_id 
    having count(1)=(select count(1) from score inner join student on score.student_id=student.id where student.name="蜘蛛"))
    and
    score.course_id
    in
    (select course_id from score inner join student on score.student_id=student.id where student.name="蜘蛛")
    # 3)根据学生id进行分组,剩下学生数count(1)=貂蝉学生所学课程数
    select student_id from score where score.student_id 
    in
    (select student_id from score 
    group by score.student_id 
    having count(1)=(select count(1) from score inner join student on score.student_id=student.id where student.name="蜘蛛"))
    and
    score.course_id
    in
    (select course_id from score inner join student on score.student_id=student.id where student.name="蜘蛛")
    group by
    score.student_id
    having count(1)=(select count(1) from score inner join student on score.student_id=student.id where student.name="蜘蛛")
    and
    score.student_id!=(select id from student where name="蜘蛛")
    # 4)最终结果
    select name from student where id in
    (select student_id from score where score.student_id 
    in
    (select student_id from score 
    group by score.student_id 
    having count(1)=(select count(1) from score inner join student on score.student_id=student.id where student.name="蜘蛛"))
    and
    score.course_id
    in
    (select course_id from score inner join student on score.student_id=student.id where student.name="蜘蛛")
    group by
    score.student_id
    having count(1)=(select count(1) from score inner join student on score.student_id=student.id where student.name="蜘蛛")
    and
    score.student_id!=(select id from student where name="蜘蛛"));
    
    ------------------------------------------------------------
    -- 15、按平均成绩倒序显示所有学生的"python"、"java"、"php"三门的课程成绩,按如下形式显示: 学生id,python,java,php,课程数,平均分
    # 1)先查询单一学生的python课程分数
    select mark from score left join course on score.course_id = course.id where course.name = "python" and score.student_id=1;
    # 2)将上面查询的结果作为列字段使用,得到最终结果
    select student_id,
    (select mark from score left join course on score.course_id = course.id where course.name = "python" and score.student_id=sc.student_id) as "python",
    (select mark from score left join course on score.course_id = course.id where course.name = "java" and score.student_id=sc.student_id) as "java",
    (select mark from score left join course on score.course_id = course.id where course.name = "php" and score.student_id=sc.student_id) as "php",
    count(course_id) as "课程数",
    avg(mark) as "平均分"
    from score as sc
    group by student_id order by avg(mark) desc;
    
    ------------------------------------------------------------
    -- 16、查询各科成绩最高和最低的分:以如下形式显示:课程id,最高分,最低分
    select course_id,max(mark) as "最高分",min(mark) as "最低分" from score group by course_id;
    
    ------------------------------------------------------------
    -- 17、统计各科各分数段人数,显示格式:课程id,课程名称,[100-85],[85-70],[70-60],[<60]
    select course_id,course.name,
    sum(case when mark between 85 and 100 then 1 else 0 end) as "[100-85]",
    sum(case when mark between 70 and 85 then 1 else 0 end) as "[85-70]",
    sum(case when mark between 60 and 70 then 1 else 0 end) as "[70-60]",
    sum(case when mark < 60 then 1 else 0 end) as "[<60]"
    from score
    inner join course
    on score.course_id=course.id
    GROUP BY score.course_id;
    
    ------------------------------------------------------------
    -- 18、查询每门课程名字及其被选修的次数
    select course.name,count(1) from score 
    inner join course on score.course_id=course.id
    group by course_id;
    
    ------------------------------------------------------------
    -- 19、查询只选修了一门课程的学生的学号和姓名
    select student_id,student.name from score
    inner join student on score.student_id=student.id
    group by student_id having count(course_id)=1;
    
    ------------------------------------------------------------
    -- 20、查询学生表中男生、女生各有多少人
    select
    sum(case when gender="男" then 1 else 0 end) as "男生",
    sum(case when gender="女" then 1 else 0 end) as "女生"
    from student
    
    ------------------------------------------------------------
    -- 21、查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程id降序排列
    select course.name,avg(mark) from score
    inner join course on score.course_id=course.id
    group by course_id
    order by avg(mark) asc,course_id desc;
    
    ------------------------------------------------------------
    -- 22、查询课程名称为"python"且分数低于60的学生姓名和分数
    select student.name,mark from score
    inner join student on score.student_id=student.id
    where mark<60 and course_id=(select id from course where name="python");
    
    ------------------------------------------------------------
    -- 23、求选了课程的学生人数
    # 方式一:
    select count(distinct student_id) from score;
    # 方式二:
    select count(1) from (select count(student_id) from score group by student_id) as a;
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  • 原文地址:https://www.cnblogs.com/believepd/p/10434768.html
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