• HW 7


    俗话说的好:自闭从不单行,永远双至。果然这一场又自闭了。C语言没学好。。。。

    Problem A: 字符串类(I)

    main 函数:

    int main()
    {
        STR e;
        STR h("Hello World!");
        char s[100001];
        cout << e.length() << " ";
        e.putline();
        cout << h.length() << " ";
        h.putline();
        while(gets(s) != NULL)
        {
            STR str(s);
            cout << str.length() << " ";
            str.putline();
        }
    }

    怎么说那,本来以为RE到绝望了。。。。。,没想到还有B题。

    总体来说还是水题,怎么说的怎么写吧。

    AC代码:

    #include <bits/stdc++.h>
    using namespace std;
    class STR
    {
        char *p;
        int len;
    public:
        STR():p(NULL),len(0){};
        STR(const char *s){len = strlen(s);p = new char[len+1];strcpy(p,s);};
        int length()
        {
            return len;
        }
        void putline()
        {
            if(p==NULL)
                cout << endl;
            else
            cout << p  << endl;
        }
        ~STR()
        {
            len = 0;
            if(p!=NULL)
                delete []p;
        }
    };
    int main()
    {
        STR e;
        STR h("Hello World!");
        char s[100001];
        cout << e.length() << " ";
        e.putline();
        cout << h.length() << " ";
        h.putline();
        while(gets(s) != NULL)
        {
            STR str(s);
            cout << str.length() << " ";
            str.putline();
        }
    }
     

    Problem B: 字符串类(II)

    main 函数:

    int main()
    {
        STR e;
        STR h("Hello World!");
        STR he = e + h;
        cout << he.length() << " ";
        he.putline();
        cout << e.length() << " ";
        e.putline();
        cout << h.length() << " ";
        h.putline();
        e += h;
        cout << e.length() << " ";
        e.putline();
        cout << h.length() << " ";
        h.putline();
     
        char s1[100001], s2[100001];
        while(gets(s1) != NULL && gets(s2) != NULL)
        {
            STR str1(s1), str2(s2);
            STR str = str1 + str2;
            cout << str.length() << " ";
            str.putline();
            cout << str1.length() << " ";
            str1.putline();
            cout << str2.length() << " ";
            str2.putline();
            str2 += str1;
            cout << str2.length() << " ";
            str2.putline();
            cout << str1.length() << " ";
            str1.putline();
        }
    }

    这个题RE到自闭,分析原因应该是忘记老师之前讲过的指针悬空问题,对于+=函数没有返回引用,也没有写拷贝构造函数,导致指针悬空,在析构的时候发生了错误。

    附博客(讲返回对象与引用区别的):

    https://www.cnblogs.com/JMLiu/p/7928425.html

    AC代码1(不返回引用):

    #include <bits/stdc++.h>
    using namespace std;
    class STR
    {
        char *p;
        int len;
        //static int num;
    public:
        STR():p(NULL),len(0){};
        STR(const char *s){len = strlen(s);p = new char[len+1];strcpy(p,s); p[len] = '';};
        STR(const STR &b){len = strlen(b.p);p = new char[len+1];strcpy(p,b.p); p[len] = '';};
        int length()
        {
            return len;
        }
        void putline()
        {
            if(p==NULL)
                cout << endl;
            else
            cout << p  << endl;
        }
        STR operator + (const STR&b)
        {
            char *s ;
            s = new char[len+b.len+1];
            strcpy(s,p);
            strcat(s,b.p);
            return STR(s);
        }
        STR operator+=(const STR &b)
        {
           STR c = *this+b;
            p  = new char[c.len+1];
            len = c.len;
            strcpy(p,c.p);
            return *this;
        }
        ~STR()
        {
            cout << "s = " <<  p << endl;
            if(len!=0)
                delete []p;
            len = 0;
    
        }
    };

    AC2(返回引用):

    #include <bits/stdc++.h>
    using namespace std;
    class STR
    {
        char *p;
        int len;
    public:
        STR():p(NULL),len(0){};
        STR(const char *s){len = strlen(s);p = new char[len+1];strcpy(p,s); p[len] = '';};
        int length()
        {
            return len;
        }
        void putline()
        {
            if(p==NULL)
                cout << endl;
            else
            cout << p  << endl;
        }
        STR operator + (const STR&b)
        {
            char *s ;
            s = new char[len+b.len+1];
            int i = 0;
            for(i = 0;i<len;i++)
                s[i] = p[i];
            for(int j = 0 ;j<b.len;i++,j++)
                s[i] = b.p[j];
            s[i] = '';
            //cout << s << endl;
            return STR(s);
        }
        STR& operator+=(const STR &b)
        {
            STR c = *this+b;
            //cout << c.p << endl;
            p = new char [c.len+1];
            strcpy(p,c.p);
            //cout << p << endl;
            len = c.len;
            return *this;
        }
        ~STR()
        {
            if(len!=0)
                delete []p;
            len = 0;
     
        }
    };

    Problem C: 学生干部虚基类:

    main 函数:

    int main( )
    {
        string name, major, post, addr, tel;
        int age;
        char sex;
        float wage;
        cin>>name>>age>>sex>>addr>>tel>>major>>post>>wage;
     
        Student_Cadre st_ca(name, age, sex,  addr, tel, major, post,wage);
        st_ca.display( );
     
        cout<<endl;
        string newAddr, newTel1, newTel2;
        cin>>newAddr>>newTel1>>newTel2;
     
        st_ca.setAddr(newAddr);
        st_ca.Student::setTel(newTel1);
        st_ca.Cadre::setTel(newTel2);
        st_ca.display( );
        return 0;
    }

    类的虚继承,打比方来说,类D继承于类B和类C,而类C和类B有相同的基类A,因此在类D中事实上存在两个类A的对象和方法,在类D中调用类A的对象或方法时,就会产生二义性,但如果采用虚拟继承,在这个继承的过程中,就只会产生一个类A的对象及方法,就不会产生二义性。

    最后CE了两发,没想到竟然是万能头害的,major居然是个关键字,自闭。。。。

    AC代码:

    #include <iostream>
    #include <string>
    using namespace std;
    class Person
    {
        string name,addr,tel;
        int age;
        char sex;
        friend class Student_Cadre;
        friend class Student;
        friend class Cadre;
    public:
        //Person(){};
        Person(string _name,int _age,char _sex,string _addr,string _tel):name(_name),sex(_sex),tel(_tel),addr(_addr),age(_age){};
        void setAddr(string _add){addr = _add;}
        void setTel(string _tel){tel = _tel;}
    };
    class Student:virtual public Person
    {
        string major;
        friend class Student_Cadre;
    public:
        //Student(){};
        Student(string _name,int _age,char _sex,string _addr,string _tel,string _major):Person(_name,_age,_sex,_addr,_tel),major(_major){};
    };
    class Cadre:virtual public Person
    {
        string post;
        friend class Student_Cadre;
    public:
       // Cadre(){};
        Cadre(string _name,int _age,char _sex,string _addr,string _tel,string _post):Person(_name,_age,_sex,_addr,_tel),post(_post){};
    };
    class Student_Cadre:public Student,public Cadre
    {
        float wages;
    public:
        Student_Cadre(string _name,int _age,char _sex,string _addr,string _tel,string _major,string _post,float _wages):Person(_name,_age,_sex,_addr,_tel),Student(_name,_age,_sex,_addr,_tel,_major),Cadre(_name,_age,_sex,_addr,_tel,_post),wages(_wages){};
        void display()
        {
            cout << "name:" << this->name << endl;
            cout << "age" << age << endl;
            cout << "sex:" << sex << endl;
            cout << "address:" << addr << endl;
            cout << "tel:" << tel << endl;
            cout << "major:" << major << endl;
            cout << "post:" << post << endl;
            cout << "wages:" << wages << endl;
        }
    };

    Problem D: 选举班干部了!

    main 函数:

    int main()
    {
        int num;
        string name, position;
        bool sex;
        int grade;
        Student *header, *student, *curStudent;
     
        cin>>name>>sex>>grade>>position;
        header = new StudentCadre(name, sex, grade,position);
        curStudent = header;
        cin>>num;
        for (int i = 0; i < num; i++)
        {
            cin>>name>>sex>>grade;
            student = new Student(name, sex, grade);
            curStudent -> setNext(student);
            curStudent = curStudent -> getNext();
        }
        ((StudentCadre*)header) -> showInfo();
        cout<<endl;
        curStudent = header;
        while (curStudent -> getNext() != NULL)
        {
            curStudent = curStudent -> getNext();
            curStudent->showInfo();
            cout<<endl;
        }
     
        curStudent = header;
        while (curStudent != NULL)
        {
            student = curStudent;
            curStudent = curStudent -> getNext();
            delete student;
        }
        return 0;
    }

    继承水题:

    #include <bits/stdc++.h>
    using namespace std;
    class Student
    {
        string name;
        bool sex;
        int grade;
        Student *next;
        friend class StudentCadre;
    public:
        Student(){};
        Student(string _name,bool _sex,int _grade):name(_name),sex(_sex),grade(_grade),next(NULL){cout << "A student named by " << name << " is created!" << endl;}
        Student(Student&b){name = b.name,sex = b.sex,grade = b.grade; *next = *(b.next);}
        void showInfo()
        {
            cout << "name = " << name <<", sex = " << sex << ", grade = "<< grade  << ";" ;
        }
        Student* getNext()
        {
            return next;
        }
        void setNext(Student *s)
        {
            next = s;
        }
        ~Student()
        {
            //delete next;
            cout << "A student named by " << name << " is erased." << endl;
        }
    };
    class  StudentCadre:public Student
    {
        string postion;
    public:
        //StudentCadre(){cout << 2 << endl;}
        StudentCadre(string _name, bool _sex, int _grade, string pos):Student(_name,_sex,_grade),postion(pos){cout << "A student cadre with position " << postion << " is created." << endl;};
        StudentCadre(StudentCadre &b)
        {
            name = b.name,sex = b.sex,grade = b.grade;
            postion = b.postion;
            *next = *(b.next);
        }
        void showInfo()
        {
            cout << "name = " << name <<", sex = " << sex << ", grade = "<< grade  << "; " << "position = " << postion << "." ;
        }
    };

    Problem E: 立体空间中的点(I)

    main 函数:

    int main()
    {
        int cases;
        cin>>cases;
        for(int i = 1; i <= cases; i++)
        {
            double x, y, z;
            int point_type;
            cin>>point_type;
            if(point_type == 2)
            {
                cin>>x>>y;
                Point p(x, y);
                p.showPoint();
            }
            if(point_type == 3)
            {
                cin>>x>>y>>z;
                Point_3D p(x, y, z);
                p.showPoint();
            }
        }
    }

    继承水,但不用继承写也能过,事实上也没有多大差别,但还是放继承的代码吧:

    #include <bits/stdc++.h>
    using namespace std;
    class Point
    {
        double x,y;
        friend class Point_3D;
    public:
        Point(){};
        Point(double _x,double _y):x(_x),y(_y){};
        void showPoint()
        {
            cout << "2D Point (" << x << "," << y << ")" << endl;
        }
    };
    class Point_3D:public Point
    {
        double z;
    public:
        Point_3D(){};
        Point_3D(double _x,double _y,double _z):Point(_x,_y),z(_z){};
        void showPoint()
        {
            cout << "3D Point (" << x << "," << y << "," << z << ")" << endl;
        }
    };

    Problem F: 立体空间中的点(II)

    mian 函数:

    int main()
    {
        cout<<"Invariable test output :"<<endl;
        Point_3D p3d;
        p3d.setPoint(-100, 0, 100);
        p3d.showPoint();
        p3d.x(0);
        p3d.y(100);
        cout<<"Point ("<<p3d.x()<<","<<p3d.y()<<","<<p3d.z()<<")"<<endl;
        cout<<"
    Test data output :"<<endl;
        int cases;
        cin>>cases;
        for(int i = 1; i <= cases; i++)
        {
            double x, y, z;
            int point_type;
            cin>>point_type;
            if(point_type == 2)
            {
                cin>>x>>y;
                Point p(x, y);
                p.showPoint();
            }
            if(point_type == 3)
            {
                cin>>x>>y>>z;
                Point_3D p(x, y, z);
                p.showPoint();
            }
        }
        cout<<"Number of 2D Points : "<<Point::showNumber() - Point_3D::showNumber()<<endl;
        cout<<"Number of 3D Points : "<<Point_3D::showNumber() - 1<<endl;
    }

    继承水:

    AC代码:

    #include <bits/stdc++.h>
    using namespace std;
    class Point
    {
        double x1,y1;
        static int N_P;
        friend class Point_3D;
    public:
        Point(){N_P++;};
        Point(double _x,double _y):x1(_x),y1(_y){N_P++;};
        void showPoint()
        {
            cout << "2D Point (" << x1 << "," << y1 << ")" << endl;
        }
        void x(double _x){x1 =_x;}
        void y(double _y){y1 = _y;}
        double x()
        {
            return x1;
        }
        double y()
        {
            return y1;
        }
        static int showNumber(){return N_P;}
    };
    class Point_3D:public Point
    {
        double z1;
        static int N_P3;
    public:
        Point_3D(){N_P3++;};
        Point_3D(double _x,double _y,double _z):Point(_x,_y),z1(_z){N_P3++;};
        double z()
        {
            return z1;
        }
        void z(double _z)
        {
            z1 = _z;
        }
        void setPoint(double _x,double _y,double _z)
        {
            x1 =_x;
            y1 = _y;
            z1 = _z;
        }
        static int showNumber()
        {
            return N_P3;
        }
     
        void showPoint()
        {
            cout << "3D Point (" << x1 << "," << y1 << "," << z1 << ")" << endl;
        }
    };
    int Point::N_P = 0;
    int Point_3D::N_P3 = 0;
    过往不念 未来不迎 当下不负
  • 相关阅读:
    saolei
    Hibernate中表与表之间的关联多对多,级联保存,级联删除
    Hibernate中表与表之间的关联一对多,级联保存和级联删除
    Hibernate中的Query对象查询所有记录
    Hibernate缓存
    hibernate简单实现连接数据库,并实现数据的操作
    Navicat注册码
    用jdbc连接数据库并简单执行SQL语句
    JDBC中的DriverManager.getConnection(url)中的参数url
    spring进行事务管理
  • 原文地址:https://www.cnblogs.com/baihualiaoluan/p/10878196.html
Copyright © 2020-2023  润新知