1.编写一个简单程序,要求数组长度为5,静态赋值10,20,30,40,50,在控制台输出该数组的值。
import java.util.*; public class C { public static void main(String[] args) { // TODO Auto-generated method stub Scanner input=new Scanner(System.in); int[] arr=new int[]{10,20,30,40,50}; for(int i=0;i<arr.length;i++){ System.out.print(arr[i]+" "); } } }
2.编写一个简单程序,要求数组长度为5,动态赋值10,20,30,40,50,在控制台输出该数组的值。
import java.util.*; public class C { public static void main(String[] args) { // TODO Auto-generated method stub int ass [] = new int [5]; Scanner sc = new Scanner(System.in); for(int a=0;a<ass.length;a++){ System.out.println("输入数字"); ass[a] = sc.nextInt(); } System.out.println("赋值结束"); } }
3.编写一个简单程序,定义整型数组,里面的元素是{23,45,22,33,56},求数组元素的和、平均值
import java.util.*; public class C { public static void main(String[] args) { // TODO Auto-generated method stub Scanner sc = new Scanner(System.in); int a[]= {23,45,22,33,56}; double sum=0; for(int i=0;i<a.length;i++) { sum+=a[i]; } System.out.println("和为:"+sum+"平均值为:"+sum/5); } }
4.在一个有8个整数(18,25,7,36,13,2,89,63)的数组中找出其中最大的数及其下标。
public class C { public static void main(String[] args) { // TODO Auto-generated method stub int[] aa = {18,25,7,36,13,2,89,63}; int[] bb = new int[aa.length]; System.arraycopy(aa, 0, bb, 0, aa.length); for(int y=0; y<bb.length-1; y++) { if(bb[y]>bb[y+1]) { int temp = bb[y]; bb[y] = bb[y+1]; bb[y+1] = temp; } } for(int element : bb) { System.out.print(element+" "); } System.out.println("-------"); System.out.println("这个数组最大的数是:"+ bb[bb.length-1]); int xiabiao = 0; for(int i=0; i<aa.length; i++) { if(aa[i]==bb[bb.length-1]) { xiabiao = i; } } System.out.println("下标为:"+xiabiao); } }
5. 将一个数组中的元素逆序存放(知识点:数组遍历、数组元素访问)
public class C { public static void main(String[] args) { // TODO Auto-generated method stub int [] a = new int [] {4,1,3,5,9,2,1}; int b; for(int i = 0; i < a.length / 2; i ++) { b = a[i]; a[i] = a[a.length - 1 - i]; a[a.length - 1 - i] = b; } for(int i = 0; i < a.length; i ++) { System.out.print(a[i] + ","); } } }