• 【平衡树】【pb_ds】 bzoj1861 [Zjoi2006]Book 书架


    需要用数组记录编号为i的书的位置,和位置i处的书的编号。

    Code:
     1 #include<cstdio>
     2 #include<ext/pb_ds/assoc_container.hpp>
     3 #include<ext/pb_ds/tree_policy.hpp>
     4 using namespace std;
     5 using namespace __gnu_cxx;
     6 using namespace __gnu_pbds;
     7 tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update> T;
     8 typedef tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update>::iterator ITER;
     9 //往bzoj上交时,请将null_type改成null_mapped_type
    10 int Pos[100001],Val[500001],a,x,n,m;
    11 char op[7];
    12 int main()
    13 {
    14     scanf("%d%d",&n,&m);
    15     for(int i=1;i<=n;i++)
    16       {
    17         scanf("%d",&Val[i+100000]);
    18         Pos[Val[i+100000]]=i+100000;
    19         T.insert(i+100000);
    20       }
    21     for(int i=1;i<=m;i++)
    22       {
    23         scanf("%s",op);
    24         if(op[0]=='T')
    25           {
    26             scanf("%d",&a);
    27             int tmp=*T.find_by_order(0);
    28             T.erase(T.lower_bound(Pos[a]));
    29             Pos[a]=tmp-1;
    30             Val[tmp-1]=a;
    31             T.insert(tmp-1);
    32           }
    33         else if(op[0]=='B')
    34           {
    35             scanf("%d",&a);
    36             int tmp=*T.find_by_order(n-1);
    37             T.erase(T.lower_bound(Pos[a]));
    38             Pos[a]=tmp+1;
    39             Val[tmp+1]=a;
    40             T.insert(tmp+1);
    41           }
    42         else if(op[0]=='I')
    43           {
    44             scanf("%d%d",&a,&x);
    45             if(x==0)
    46               continue;
    47             ITER it=T.lower_bound(Pos[a]);
    48             ITER it_Beside=it;
    49             if(x==1)
    50               it_Beside++;
    51             else
    52               it_Beside--;
    53             swap(Val[*it],Val[*it_Beside]);
    54             swap(Pos[Val[*it]],Pos[Val[*it_Beside]]);
    55           }
    56         else if(op[0]=='A')
    57           {
    58             scanf("%d",&a);
    59             printf("%d
    ",T.order_of_key(Pos[a]));
    60           }
    61         else
    62           {
    63             scanf("%d",&a);
    64             printf("%d
    ",Val[*T.find_by_order(a-1)]);
    65           }
    66       }
    67     return 0;
    68 }
    ——The Solution By AutSky_JadeK From UESTC 转载请注明出处:http://www.cnblogs.com/autsky-jadek/
  • 相关阅读:
    Azure Cognitive Service 访问优化
    Azure Managed Disk 共享不灵,EventGrid + LogicApp 来搞
    AZURE ACI -- 无服务器化容器解决方案
    Global Azure 与 China Azure 互联
    小总结
    存储过程及Comm.cs类的创建
    DataGrid1
    根据经纬度和半径计算经纬度范围
    CheckBoxJS选中与反选得到Value
    每天学一点-Jquery判断checkbox是否为选中状态
  • 原文地址:https://www.cnblogs.com/autsky-jadek/p/3959463.html
Copyright © 2020-2023  润新知