实验9：Problem E: 点在圆内吗？

有个坑是：

The Point (0, 0) is created!
A Point (0, 0) is copied!
A Point (0, 0) is erased!

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Problem E: 点在圆内吗？

Time Limit: 1 Sec Memory Limit: 128 MB
Submit: 553 Solved: 277
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Description

定义一个Point类和Circle类，用于判断给定的一系列的点是否在给定的圆内。

其中，Point类：

1.有2个成员x和y，分别为其横坐标和纵坐标；1个静态成员numOfPoints，用于计算生成的点的个数。

2.具有构造函数、析构函数和拷贝构造函数，具体格式输出根据样例自行判断。

3. 具有静态方法int getNumOfPoints()，用于返回numOfPoints的值。

4. 具有int getX()和int getY()方法，用于获取横坐标和纵坐标。

Circle类：

1. 拥有Point类的对象center，表示圆心坐标。拥有radius对象，表示圆的半径；1个静态成员numOfCircles，用于指示生成了多少个圆对象。

2. 具有构造函数、析构函数和拷贝构造函数，具体格式根据样例自行判断。

3.具有静态方法int getNumOfCircles()，返回numOfCircles的值。

4. 具有getCenter()方法，返回圆心坐标。注意：根据输出结果判断返回值类型。

5. 具有bool pointInCircle(Point &)方法，用于判断给定的点是否在当前圆内。是则返回true，否则返回false。

Input

输入分多行。

第一行M>0，表示有M个测试用例。

每个测试用例又包括多行。第1行包含3个整数，分别为一个圆的横坐标、纵坐标和半径。第2行N>0，表示之后又N个点，每个点占一行，分别为其横坐标和纵坐标。

所有输入均为整数，且在int类型范围内。

Output

输出见样例。注意：在圆的边上的点，不在圆内。

Sample Input

2 0 0 10 3 2 2 11 11 10 0 1 1 20 3 2 2 1 1 100 100

Sample Output

The Point (0, 0) is created! Now, we have 1 points. The Point (1, 1) is created! Now, we have 2 points. A circle at (1, 1) and radius 1 is created! Now, we have 1 circles. We have 2 points and 1 circles now. The Point (0, 0) is created! Now, we have 3 points. A Point (0, 0) is copied! Now, we have 4 points. A Point (0, 0) is copied! Now, we have 5 points. A circle at (0, 0) and radius 10 is created! Now, we have 2 circles. A Point (0, 0) is erased! Now, we have 4 points. The Point (2, 2) is created! Now, we have 5 points. (2, 2) is in the circle at (0, 0). The Point (11, 11) is created! Now, we have 6 points. (11, 11) is not in the circle at (0, 0). The Point (10, 0) is created! Now, we have 7 points. (10, 0) is not in the circle at (0, 0). A Point (0, 0) is erased! Now, we have 6 points. A circle at (0, 0) and radius 10 is erased! Now, we have 1 circles. A Point (0, 0) is erased! Now, we have 5 points. The Point (1, 1) is created! Now, we have 6 points. A Point (1, 1) is copied! Now, we have 7 points. A Point (1, 1) is copied! Now, we have 8 points. A circle at (1, 1) and radius 20 is created! Now, we have 2 circles. A Point (1, 1) is erased! Now, we have 7 points. The Point (2, 2) is created! Now, we have 8 points. (2, 2) is in the circle at (1, 1). The Point (1, 1) is created! Now, we have 9 points. (1, 1) is in the circle at (1, 1). The Point (100, 100) is created! Now, we have 10 points. (100, 100) is not in the circle at (1, 1). A Point (1, 1) is erased! Now, we have 9 points. A circle at (1, 1) and radius 20 is erased! Now, we have 1 circles. A Point (1, 1) is erased! Now, we have 8 points. We have 8 points, and 1 circles. A circle at (1, 1) and radius 1 is erased! Now, we have 0 circles. A Point (1, 1) is erased! Now, we have 7 points. A Point (0, 0) is erased! Now, we have 6 points.

HINT

Append Code

append.cc,

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GPL2.0 2003-2011 HUSTOJ Project TEAM
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#include<iostream>
using namespace std;
class Point{
public:
    int x,y;
    static int numOfPoints;
    Point(int a=0,int b=0):x(a),y(b){numOfPoints++;cout<<"The Point ("<<x<<", "<<y<<") is created! Now, we have "<<numOfPoints<<" points."<<endl;}
    ~Point(){numOfPoints--;cout<<"A Point ("<<x<<", "<<y<<") is erased! Now, we have "<<numOfPoints<<" points."<<endl;}
    Point(const Point&p){numOfPoints++;x=p.x;y=p.y;cout<<"A Point ("<<x<<", "<<y<<") is copied! Now, we have "<<numOfPoints<<" points."<<endl;}
    static int getNumOfPoints(){return numOfPoints;}
    int getX(){return x;}
    int getY(){return y;}

};
class Circle{
public:
    Point center;
    int radius;
    static int numOfCircles;
    Circle(int a,int b,int c):center(a,b),radius(c){numOfCircles++;cout<<"A circle at ("<<center.x<<", "<<center.y<<") and radius "<<radius<<" is created! Now, we have "<<numOfCircles<<" circles."<<endl;}
    Circle(Point p,int r):center(p),radius(r){numOfCircles++;cout<<"A circle at ("<<center.x<<", "<<center.y<<") and radius "<<radius<<" is created! Now, we have "<<numOfCircles<<" circles."<<endl;}
    ~Circle(){numOfCircles--;cout<<"A circle at ("<<center.x<<", "<<center.y<<") and radius "<<radius<<" is erased! Now, we have "<<numOfCircles<<" circles."<<endl;}
    Circle(const Circle &c){numOfCircles++;center.x=c.center.x;center.y=c.center.y;radius=c.radius;cout<<"A circle at ("<<center.x<<", "<<center.y<<") and radius "<<radius<<" is created! Now, we have "<<numOfCircles<<" circles."<<endl;}
    static int getNumOfCircles(){return numOfCircles;}
    Point &getCenter(){return center;}
    bool pointInCircle(Point &p){if((p.x-center.x)*(p.x-center.x)+(p.y-center.y)*(p.y-center.y)<radius*radius) return true;else return false;}
};
int Point::numOfPoints=0;
int Circle::numOfCircles=0;
int main()
{
    int cases,num;
    int x, y, r, px, py;
    Point aPoint(0,0), *bPoint;
    Circle aCircle(1,1,1);
    cin>>cases;
    cout<<"We have "<<Point::getNumOfPoints()<<" points and "<<Circle::getNumOfCircles()<<" circles now."<<endl;
    for (int i = 0; i < cases; i++)
    {
        cin>>x>>y>>r;
        bPoint = new Point(x,y);
        Circle circle(*bPoint, r);
        cin>>num;
        for (int j = 0; j < num; j++)
        {
            cin>>px>>py;
            if (circle.pointInCircle(*(new Point(px, py))))
            {
                cout<<"("<<px<<", "<<py<<") is in the circle at (";
                cout<<circle.getCenter().getX()<<", "<<circle.getCenter().getY()<<")."<<endl;
            }
            else
            {
                cout<<"("<<px<<", "<<py<<") is not in the circle at (";
                cout<<circle.getCenter().getX()<<", "<<circle.getCenter().getY()<<")."<<endl;
            }
        }
        delete bPoint;
    }
    cout<<"We have "<<Point::getNumOfPoints()<<" points, and "<<Circle::getNumOfCircles()<<" circles."<<endl;
    return 0;
}