• 实验9:Problem D: 从点到面


     

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    Problem D: 从点到面

    Problem D: 从点到面

    Time Limit: 1 Sec  Memory Limit: 128 MB
    Submit: 529  Solved: 332
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    Description

    一个矩形可以由左上角和右下角的顶点而唯一确定。现在请定义两个类:Point和Rectangle。

    其中Point类有x和y两个属性(均为int类型),表示二维空间内一个点的横纵坐标,并具有相应的构造函数、析构函数和拷贝构造函数。此外,还有getX()和getY()方法用以得到一个点的坐标值。

    Rectangle类有leftTop和rightBottom两个属性(均为Point类的对象),表示一个矩形的左上角和右下角的两个点,并具有相应的构造函数、析构函数。此外,还有getLeftTop()、getRightBottom()方法用于获取相应的左上角点、右下角点,getArea()方法用以获取面积。

    Input

    输入有多行。

    第一行是一个正整数M,表示后面有M个测试用例。

    每个测试用例占一行,包括4个正整数,分别为左上角的横坐标、纵坐标,右下角的横坐标、纵坐标。

    注意:

    1.请根据输出样例判断两个类中相应方法的书写方法。

    2. 假定屏幕的左下角为坐标原点。

    Output

    输出见样例。

    Sample Input

    1 10 10 20 0

    Sample Output

    A point (10, 10) is created! A point (20, 0) is created! A rectangle (10, 10) to (20, 0) is created! Area: 100 Left top is (10, 10) A point (20, 0) is copied! A point (20, 0) is copied! Right bottom is (20, 0) A point (20, 0) is erased! A point (20, 0) is erased! A rectangle (10, 10) to (20, 0) is erased! A point (20, 0) is erased! A point (10, 10) is erased!

    HINT

     

    Append Code

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    #include<iostream>
    using namespace std;
    class Point{
        friend class Rectangle;
    public:
        int x,y;
        Point(int a,int b):x(a),y(b){cout<<"A point ("<<x<<", "<<y<<") is created!"<<endl;}
        ~Point(){cout<<"A point ("<<x<<", "<<y<<") is erased!"<<endl;}
        Point(const Point &p){x=p.x;y=p.y;cout<<"A point ("<<x<<", "<<y<<") is copied!"<<endl;}
        int getX(){return x;}
        int getY(){return y;}
    
    };
    class Rectangle{
        friend class Point;
    public:
        Point leftTop,rightBottom;
        Rectangle(Point p,Point q):leftTop(p),rightBottom(q){cout<<"A rectangle ("<<leftTop.x<<", "<<leftTop.y<<") to ("<<rightBottom.x<<", "<<rightBottom.y<<") is created!"<<endl;}
        Rectangle(int a,int b,int c,int d):leftTop(a,b),rightBottom(c,d){cout<<"A rectangle ("<<leftTop.x<<", "<<leftTop.y<<") to ("<<rightBottom.x<<", "<<rightBottom.y<<") is created!"<<endl;}
        ~Rectangle(){cout<<"A rectangle ("<<leftTop.x<<", "<<leftTop.y<<") to ("<<rightBottom.x<<", "<<rightBottom.y<<") is erased!"<<endl;}
        Point &getLeftTop(){return leftTop;}
        Point getRightBottome(){return rightBottom;}
        int getArea(){return (rightBottom.x-leftTop.x)*(leftTop.y-rightBottom.y);}
    };
    int main()
    {
        int cases;
        int x1, y1, x2, y2;
    
        cin>>cases;
        for (int i = 0; i < cases; i++)
        {
            cin>>x1>>y1>>x2>>y2;
            Rectangle rect(x1,y1,x2,y2);
            cout<<"Area: "<<rect.getArea()<<endl;
            cout<<"Left top is ("<<rect.getLeftTop().getX()<<", "<<rect.getLeftTop().getY()<<")"<<endl;
            cout<<"Right bottom is ("<<rect.getRightBottome().getX()<<", "<<rect.getRightBottome().getY()<<")"<<endl;
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/auto1945837845/p/5447296.html
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