• POJ 2676, Sudoku


    Time Limit: 2000MS  Memory Limit: 65536K
    Total Submissions: 5414  Accepted: 2567  Special Judge


    Description
    Sudoku is a very simple task. A square table with 9 rows and 9 columns is divided to 9 smaller squares 3x3 as shown on the Figure. In some of the cells are written decimal digits from 1 to 9. The other cells are empty. The goal is to fill the empty cells with decimal digits from 1 to 9, one digit per cell, in such way that in each row, in each column and in each marked 3x3 subsquare, all the digits from 1 to 9 to appear. Write a program to solve a given Sudoku-task.


    Input
    The input data will start with the number of the test cases. For each test case, 9 lines follow, corresponding to the rows of the table. On each line a string of exactly 9 decimal digits is given, corresponding to the cells in this line. If a cell is empty it is represented by 0.

    Output
    For each test case your program should print the solution in the same format as the input data. The empty cells have to be filled according to the rules. If solutions is not unique, then the program may print any one of them.

    Sample Input
    1
    103000509
    002109400
    000704000
    300502006
    060000050
    700803004
    000401000
    009205800
    804000107

    Sample Output
    143628579
    572139468
    986754231
    391542786
    468917352
    725863914
    237481695
    619275843
    854396127

    Source
    Southeastern Europe 2005


    // POJ2676.cpp : Defines the entry point for the console application.
    //

    #include 
    <iostream>
    #include 
    <iterator>
    using namespace std;

    inline 
    int getsq(int i, int j)
    {
        
    if (i < 3 && j < 3return 0;
        
    else if (i < 3 && j < 6return 1;
        
    else if (i < 3 && j < 9return 2;
        
    else if (i < 6 && j < 3return 3;
        
    else if (i < 6 && j < 6return 4;
        
    else if (i < 6 && j < 9return 5;
        
    else if (i < 9 && j < 3return 6;
        
    else if (i < 9 && j < 6return 7;
        
    else if (i < 9 && j < 9return 8;
        
    return -1;
    }

    static char board[10][10];
    static unsigned int sq[9];
    static unsigned int row[9];
    static unsigned int col[9];
    bool DFS()
    {
        
    //check board
        int ii, jj;
        
    bool find = false;
        
    for (int i = 0; i < 9++i)
        {
            
    for (int j = 0; j < 9++j)
                
    if (board[i][j]=='0')
                {
                    find 
    = true;
                    ii 
    = i; 
                    jj 
    = j;
                    
    break;
                };
            
    if (find == truebreak;
        }
        
    if (find == falsereturn true;

        
    int kk = getsq(ii,jj);
        
    int avl = row[ii] & col[jj] & sq[kk];
        
    for (int l = 0; l < 9++l)
            
    if (((avl >> l) & 1== 1)
            {
                row[ii] 
    &= ~(1 << l);
                col[jj] 
    &= ~(1 << l);
                sq[kk] 
    &= ~(1 << l);
                board[ii][jj] 
    = l + '1';
                
    if (DFS()) return true;
                board[ii][jj] 
    = '0';
                row[ii] 
    |= (1 << l);
                col[jj] 
    |= (1 << l);
                sq[kk] 
    |= (1 << l);
            };

        
    return false;
    };
    int main(int argc, char* argv[])
    {
        
    int cases;
        scanf(
    "%d\n"&cases);

        
    for (int c = 0; c < cases; ++c)
        {
            
    for (int i = 0; i < 9++i)
                gets(board[i]);

            
    //used
            memset(sq, 0sizeof(sq));
            memset(row, 
    0sizeof(row));
            memset(col, 
    0sizeof(col));
            
    for (int i = 0; i < 9++i)
                
    for (int j = 0; j < 9++j)
                    
    if (board[i][j]!='0')
                    {
                        row[i] 
    |= 1 << (board[i][j] - '1');
                        col[j] 
    |= 1 << (board[i][j] - '1');
                        sq[getsq(i,j)] 
    |= 1 << (board[i][j] - '1');
                    };
            
    //availble
            for (int i = 0; i < 9++i)
            {
                row[i] 
    = ~row[i];
                col[i] 
    = ~col[i];
                sq[i] 
    = ~sq[i];
            }
            
            DFS();

            
    for (int i = 0; i < 9++i) 
            {
                copy(
    &board[i][0], &board[i][9], ostream_iterator<char>(cout));
                cout
    <<endl;
            }
        }
        
    return 0;
    }

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  • 原文地址:https://www.cnblogs.com/asuran/p/1580878.html
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