• POJ 1094, Sorting It All Out


    拓扑排序


    Description
    An ascending sorted sequence of distinct values is one in which some form of a less-than operator is used to order the elements from smallest to largest. For example, the sorted sequence A, B, C, D implies that A < B, B < C and C < D. in this problem, we will give you a set of relations of the form A < B and ask you to determine whether a sorted order has been specified or not.

     

    Input
    Input consists of multiple problem instances. Each instance starts with a line containing two positive integers n and m. the first value indicated the number of objects to sort, where 2 <= n <= 26. The objects to be sorted will be the first n characters of the uppercase alphabet. The second value m indicates the number of relations of the form A < B which will be given in this problem instance. Next will be m lines, each containing one such relation consisting of three characters: an uppercase letter, the character "<" and a second uppercase letter. No letter will be outside the range of the first n letters of the alphabet. Values of n = m = 0 indicate end of input.

    Output
    For each problem instance, output consists of one line. This line should be one of the following three:

    Sorted sequence determined after xxx relations: yyy...y.
    Sorted sequence cannot be determined.
    Inconsistency found after xxx relations.

    where xxx is the number of relations processed at the time either a sorted sequence is determined or an inconsistency is found, whichever comes first, and yyy...y is the sorted, ascending sequence.

    Sample Input
    4 6
    A<B
    A<C
    B<C
    C<D
    B<D
    A<B
    3 2
    A<B
    B<A
    26 1
    A<Z
    0 0

    Sample Output
    Sorted sequence determined after 4 relations: ABCD.
    Inconsistency found after 2 relations.
    Sorted sequence cannot be determined.

    Source
    East Central North America 2001

    *check loop first, then ambiguous


    // POJ1094.cpp : Defines the entry point for the console application.
    //

    #include 
    <iostream>
    #include 
    <string>
    #include 
    <algorithm>
    using namespace std;

    string TopSort(bool d[26][26], int in[26], int n)
    {
        
    int indegree[26];
        copy (
    &in[0], &in[n], &indegree[0]);

        
    int cnt = n;
        
    string  str;
        
    bool ambiguous = false;
        
    while (cnt > 0)
        {
            
    int zeros = std::count(&indegree[0],&indegree[n], 0);
            
    if (zeros == 0)
            {
                
    return "1"// loop
            }
            
    else if (zeros > 1)
            {
                ambiguous 
    = true//ambiguous
            }
            
            
    int pos = std::distance(&indegree[0],std::find(&indegree[0],&indegree[n], 0));

            
    for (int i = 0; i < n; ++i)
                
    if (d[pos][i] == true--indegree[i];

            
    --cnt;
            indegree[pos] 
    = -1;
            str 
    += string(1,(char)(pos + 'A'));
        }

        
    if (ambiguous == true)return "2";
        
    return str; //OK
    }

    int main(int argc, char* argv[])
    {
        
    int n,m;
        
    int in[26];
        
    bool d[26][26];
        
    string line;
        
    while(cin >> n >> m && n != 0 && m != 0)
        {
            memset(
    in0sizeof(in));
            memset(d, 
    0sizeof(d));
            
    string result = "";
            
    int step = 0;
            
    for (int i = 1; i <= m; ++i)
            {
                cin 
    >> line;
                
    if (d[line[0- 'A'][line[2- 'A']==false)
                {
                    d[line[
    0- 'A'][line[2- 'A'= true;
                    
    ++in[line[2- 'A'];
                    
    if (result == ""||result == "2")
                    {
                        result 
    = TopSort(d, in, n); 
                        step 
    = i;
                    }
                }
            }
            
            
    if (result == "1")
            {
                cout 
    << "Inconsistency found after "<<step<<" relations.\n";
            }
            
    else if (result == "2")
            {
                cout 
    << "Sorted sequence cannot be determined.\n";
            }
            
    else
            {
                cout 
    << "Sorted sequence determined after "<<step<<" relations: "<<result<<".\n";
            }
        };
        
    return 0;
    }

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  • 原文地址:https://www.cnblogs.com/asuran/p/1577863.html
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