1.题目
list3 = [
{'name':'Alex','hobby':'抽烟'},
{'name':'Alex', 'hobby':'喝酒'},
{'name':'Alex', 'hobby':'烫头'},
{'name':'Alex', 'hobby':'Massage'},
{'name':'wusir', 'hobby':'喊麦'},
{'name':'wusir', 'hobby':'街舞'},]
# 将以上列表转化成下列样式:
# list4 = [
# {'name':'alex','hobby_list':['抽烟','喝酒','烫头','Message']},
# {'name':'wusir','hobby_list':['喊麦','街舞']}]
2.解答
list4 = []
for i in list3: # 循环list3, 得出每一个字典, ①
# 第二次添加时候,判断i['name']在不在新建的字典里面 ,就要循环新形成的list4这个列表,找到name的对应值
for j in list4:
if j['name'] == i['name']:
j['hobby_list'].append(i['hobby'])
break
else:
dic = {} # 建立一个新字典②
dic['name'] = i['name'] # 将每个值赋值到新的字典里面③
dic['hobby_list'] = [i['hobby']] # 将每个值赋值到新的字典里面,这里是一个列表③
list4.append(dic) # 将字典添加到list4里面 ④
for ren in list3: # {"name": "alex", "hobby": "抽烟"},
for el in list4:
if el['name'] == ren['name']:
el['hobby_list'].append(ren['hobby'])
break
else:
dic = {}
dic['name'] = ren['name']
dic['hobby_list'] = [ren['hobby']]
list4.append(dic) # 第一个人进去
print(list4)