832Flipping an Image

/*
Given a binary matrix A, we want to flip the image horizontally, then invert it, and return the resulting image.

To flip an image horizontally means that each row of the image is reversed.  For example, flipping [1, 1, 0] horizontally results in [0, 1, 1].

To invert an image means that each 0 is replaced by 1, and each 1 is replaced by 0. For example, inverting [0, 1, 1] results in [1, 0, 0].

Example 1:

Input: [[1,1,0],[1,0,1],[0,0,0]]
Output: [[1,0,0],[0,1,0],[1,1,1]]
Explanation: First reverse each row: [[0,1,1],[1,0,1],[0,0,0]].
Then, invert the image: [[1,0,0],[0,1,0],[1,1,1]]

Example 2:

Input: [[1,1,0,0],[1,0,0,1],[0,1,1,1],[1,0,1,0]]
Output: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
Explanation: First reverse each row: [[0,0,1,1],[1,0,0,1],[1,1,1,0],[0,1,0,1]].
Then invert the image: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]

Notes:

    1 <= A.length = A[0].length <= 20
    0 <= A[i][j] <= 1

/*
解题思路，先翻转数组，然后把0与1互换结束，很简单
*/
class Solution {
    public int[][] flipAndInvertImage(int[][] A) {
        int m = A.length;
        int n = A[0].length;
        int temp;
        for(int k=0;k<m;k++){
            for( int i = 0 ; i < n/2; i++ ){
                temp        =  A[k][i];
                A[k][i]     =  A[k][n-i-1];
                A[k][n-i-1] =  temp;
            }
        }
        
        for(int i=0;i<m;i++){
            for(int j=0;j<n;j++){
                if(A[i][j]==1)
                    A[i][j]=0;
                else
                    A[i][j]=1;
            }
        }
        
        return A;
    }
}