Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given "egg"
, "add"
, return true.
Given "foo"
, "bar"
, return false.
Given "paper"
, "title"
, return true.
Note:
You may assume both s and t have the same length.
解题思路:
isomorphic a 同形的,同构的
此题非常类似 Leetcode Word Pattern .
用HashMap, s 里是key, t 里是value. 每次比较,首先检查是否已有该key, 若有,检查对应value 是否相等,不等 return false; 若没有,检查value 是否已存在map里,若有,则two characters may map to the same character, return false, 若没有,put to map.
Java code:
public boolean isIsomorphic(String s, String t) { if(s.length() != t.length()){ return false; } Map<Character, Character> map = new HashMap<Character, Character>(); for(int i = 0; i < t.length(); i++) { if(map.containsKey(s.charAt(i))){ if(map.get(s.charAt(i)) != t.charAt(i)){ return false; } }else { if(map.containsValue(t.charAt(i))){ return false; }else { map.put(s.charAt(i), t.charAt(i)); } } } return true; }