• 分位数介绍


    1.分位数计算案例

     Ex1: Given a data = [6, 47, 49, 15, 42, 41, 7, 39, 43, 40, 36],求Q1, Q2, Q3, IQR

     步骤:

      1. 排序,从小到大排列data,data = [6, 7, 15, 36, 39, 40, 41, 42, 43, 47, 49]

      2. 计算分位数的位置

      3. 给出分位数

     实例:

      pos = (n+1)*p,n为数据的总个数,p为0-1之间的值

      Q1的pos = (11 + 1)*0.25 = 3 (p=0.25) Q1=15

      Q2的pos = (11 + 1)*0.5 = 6 (p=0.5) Q2=40

      Q3的pos = (11 + 1)*0.75 = 9 (p=0.75) Q3=43

      IQR = Q3 - Q1 = 28

     代码:

    import math
    def quantile_p(data, p):
        pos = (len(data) + 1)*p
        pos_integer = int(math.modf(pos)[1])
        pos_decimal = pos - pos_integer
        Q = data[pos_integer - 1] + (data[pos_integer] - data[pos_integer - 1])*pos_decimal
        return Q
    
    data = [6, 7, 15, 36, 39, 40, 41, 42, 43, 47, 49]
    Q1 = quantile_p(data, 0.25)
    print("Q1:", Q1)
    Q2 = quantile_p(data, 0.5)
    print("Q2:", Q2)
    Q3 = quantile_p(data, 0.75)
    print("Q3:", Q3)
    

     计算方式二:

      pos = 1+ (n-1)*p,n为数据的总个数,p为0-1之间的值

      Q1的pos = 1 + (11 - 1)*0.25 = 3.5 (p=0.25) Q1=25.5

      Q2的pos = 1 + (11 - 1)*0.5 = 6 (p=0.5) Q2=40

      Q3的pos = 1 + (11 - 1)*0.75 = 8.5 (p=0.75) Q3=42.5

     代码:

    import math
    def quantile_p(data, p):
        pos = 1 + (len(data)-1)*p
        pos_integer = int(math.modf(pos)[1])
        pos_decimal = pos - pos_integer
        Q = data[pos_integer - 1] + (data[pos_integer] - data[pos_integer - 1])*pos_decimal
        return Q
    data = [6, 7, 15, 36, 39, 40, 41, 42, 43, 47, 49]
    Q1 = quantile_p(data, 0.25)
    print("Q1:", Q1)
    Q2 = quantile_p(data, 0.5)
    print("Q2:", Q2)
    Q3 = quantile_p(data, 0.75)
    print("Q3:", Q3)
    

     示例2:

    import math
    def quantile_p(data, p):
        data.sort()
        pos = (len(data) + 1)*p
        pos_integer = int(math.modf(pos)[1])
        pos_decimal = pos - pos_integer
        Q = data[pos_integer - 1] + (data[pos_integer] - data[pos_integer - 1])*pos_decimal
        return Q
    
    data = [7, 15, 36, 39, 40, 41]
    Q1 = quantile_p(data, 0.25)
    print("Q1:", Q1)
    Q2 = quantile_p(data, 0.5)
    print("Q2:", Q2)
    Q3 = quantile_p(data, 0.75)
    print("Q3:", Q3)
    

     计算结果:

      Q1 = 7 +(15-7)×(1.75 - 1)= 13

      Q2 = 36 +(39-36)×(3.5 - 3)= 37.5

      Q3 = 40 +(41-40)×(5.25 - 5)= 40.25

     分位数计算法二:

     结果:

      Q1: 20.25

      Q2: 37.5

      Q3: 39.75

    2. 分位数解释

     概念:把给定的乱序数值由小到大排列并分成四等份,处于三个分割点位置的数值就是四分位数。

     第1四分位数 (Q1),又称“较小四分位数”,等于该样本中所有数值由小到大排列后第25%的数字。

     第2四分位数 (Q2),又称“中位数”,等于该样本中所有数值由小到大排列后第50%的数字。

     第3四分位数 (Q3),又称“较大四分位数”,等于该样本中所有数值由小到大排列后第75%的数字。

     四分位距(InterQuartile Range, IQR)= 第3四分位数与第1四分位数的差距

     确定p分位数位置的两种方法

      position = (n+1)*p

      position = 1 + (n-1)*p

     利用pandas求

    import pandas as pd
    import numpy as np
    dt = pd.Series(np.array([6, 47, 49, 15, 42, 41, 7, 39, 43, 40, 36])
    print("数据格式:")
    print(dt)
    print('Q1:', df.quantile(0.25))
    print('Q2:', df.quantile(0.5))
    print('Q3:', df.quantile(0.75))
    

    3.去噪

    import pandas as pd
    import numpy as np
    import matplotlib as mpl
    import matplotlib.pyplot as plt
    import seaborn as sns
    
    #解决乱码和负值的负号不出现问题
    mpl.rcParams['font.sans-serif'] = ['SimHei']
    mpl.rcParams['axes.unicode_minus'] = False
    # 使显示图标自适应
    mpl.rcParams['figure.autolayout'] = True
    
    #包装了一个异常值处理的代码,可以调用
    def outliers_proc(data, col_name, scale=3):
        """
        用于清洗异常值,默认box_plot(scale=3)进行清洗
        param data: 接收pandas数据格式
        param col_name: pandas列名
        param scale: 尺度
        """
            
        def box_plot_outliers(data_ser, box_scale):
            """
            利用箱线图去除异常值
            :param data_ser: 接收 pandas.Series 数据格式
            :param box_scale: 箱线图尺度
            """
            iqr = box_scale * (data_ser.quantile(0.75) - data_ser.quantile(0.25))
            val_low = data_ser.quantile(0.25) - iqr
            val_up = data_ser.quantile(0.75) + iqr
            rule_low = (data_ser < val_low)
            rule_up = (data_ser > val_up)
            return (rule_low,rule_up),(val_low,val_up)
        
        data_n = data.copy()
        data_serier = data_n[col_name]
        rule, value = box_plot_outliers(data_serier,box_scale=scale)
        index = np.arange(data_serier.shape[0])[rule[0]|rule[1]]
        print("Delete number is:{}".format(len(index)))
        data_n = data_n.drop(index)
        data_n.reset_index(drop=True, inplace=True)
        print("Now column number is:{}".format(data_n.shape[0]))
        index_low = np.arange(data_serier.shape[0])[rule[0]]
        outliers = data_serier.iloc[index_low]
        print("Description of data less than the lower bound is:")
        print(pd.Series(outliers).describe())
        index_up = np.arange(data_serier.shape[0])[rule[1]]
        outliers = data_serier.iloc[index_up]
        print("Description of data larger than the upper bound is:")
        print(pd.Series(outliers).describe())
        
        fig, ax = plt.subplots(1,2, figsize=(10,7))
        sns.boxplot(y=data[col_name],data=data,palette="Set1",ax=ax[0])
        sns.boxplot(y=data_n[col_name],data=data_n,palette="Set1",ax=ax[1])
        return data_n
    

     

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  • 原文地址:https://www.cnblogs.com/always-fight/p/14217701.html
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