leetcode--155. Min Stack

Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.

• push(x) -- Push element x onto stack.
• pop() -- Removes the element on top of the stack.
• top() -- Get the top element.
• getMin() -- Retrieve the minimum element in the stack.

Example:

MinStack minStack = new MinStack();
minStack.push(-2);
minStack.push(0);
minStack.push(-3);
minStack.getMin();   --> Returns -3.
minStack.pop();
minStack.top();      --> Returns 0.
minStack.getMin();   --> Returns -2.


将min设成long是因为可能是Integer.MAX_VALUE-Integer.MIN_VALUE
栈里存储的是push的值与最小值的差值。如果，差值小于零，说明push的值比最小值还要小，当取出的时候如果是小于零的值，取出的值就是min同时更新min

class MinStack {
    long min;
    Stack<Long> st;
    /** initialize your data structure here. */
    public MinStack() {
        st=new Stack<>();
    }
    
    public void push(int x) {
        if(st.isEmpty()){
            st.push(0L);
            min=x;
        }
        else{
            st.push(x-min);
            if(x<min)
                min=x;
        }
    }
    
    public void pop() {
        if(st.isEmpty())return;
        long p=st.pop();
        if(p<0)
            min=min-p;
    }
    
    public int top() {
        long t=st.peek();
        if(t<0)
            return (int)min;
        else
            return (int)(t+min);
    }
    
    public int getMin() {
        return (int)min;
    }
}

这还有个绝妙的做法

class MinStack {
    int min = Integer.MAX_VALUE;
    Stack<Integer> stack = new Stack<Integer>();
    public void push(int x) {
        // only push the old minimum value when the current 
        // minimum value changes after pushing the new value x
        if(x <= min){          
            stack.push(min);
            min=x;
        }
        stack.push(x);
    }

    public void pop() {
        // if pop operation could result in the changing of the current minimum value, 
        // pop twice and change the current minimum value to the last minimum value.
        if(stack.pop() == min) min=stack.pop();
    }

    public int top() {
        return stack.peek();
    }

    public int getMin() {
        return min;
    }
}