UVA489

题意：就是给出一个字符串，让你去一个一个猜测，相同字母算一次，如果是之前猜过的也算错，如果你在错7次前猜对就算你赢，文章中是LRJ的例题代码。

#include<stdio.h>
#include<string.h>
#define maxn 100
int left, chance;
char s[maxn], s2[maxn];
int win, lose;

void guess(char ch) {
  int bad = 1;
  for(int i = 0; i < strlen(s); i++)
    if(s[i] == ch) { left--; s[i] = ' '; bad = 0; }
  if(bad) --chance;
  if(!chance) lose = 1;
  if(!left) win = 1;
}

int main() {
  int rnd;
  while(scanf("%d%s%s", &rnd, s, s2) == 3 && rnd != -1) {
    printf("Round %d
", rnd);
    win = lose = 0;
    left = strlen(s);
    chance = 7;
    for(int i = 0; i < strlen(s2); i++) {
      guess(s2[i]);
      if(win || lose) break;
    }
    if(win) printf("You win.
");
    else if(lose) printf("You lose.
");
    else printf("You chickened out.
");
  }
  return 0;
}

#include<cstdio>
#include<cstring>
#include <iostream>
using namespace std;
int main()
{
    int n;
    while(scanf("%d",&n)!=EOF && n!=-1)
    {
        char str1[1005],str2[1005];
        int a[27],b[27];
        printf("Round %d
",n);
        scanf("%s%s",str1,str2);
        int len1=strlen(str1);
        int len2=strlen(str2);
        memset(a,0,sizeof(a));
        memset(b,1,sizeof(b));
        int x=0,y=0,z=0,t=0;
        for(int i=0;i<len1;++i)
        {
            a[str1[i]-'a']=1;
        }
        for(int i=0;i<len1;++i)
        {
            if(a[str1[i]-'a']==1 && b[str1[i]-'a'])
            {
                t++;
                b[str1[i]-'a']=0;
            }
        }
        for(int i=0;i<len2;++i)
        {
            if(a[str2[i]-'a']==1)
            {
                x++;
                a[str2[i]-'a']=-1;
            }
            else if(a[str2[i]-'a']==0)
                y++;
            else
                z++;
            if(y>6 || x-z>=t)
                break;
        }
        if(y>6)
            printf("You lose.
");
        else if(x-z>=t)
            printf("You win.
");
        else
            printf("You chickened out.
");
    }
    return 0;
}