算法简述
ac自动机是一类在字典树上进行kmp的算法。
学习ac自动机一般考点都在于对字典树上的点做处理,一般考的都是在自动机上的dp,而这类的dp中几乎必定有一维表示的是自动机上的点。
模板
#include<iostream>
#include<string.h>
#include<stdio.h>
#include<algorithm>
#include<queue>
using namespace std;
const int maxa = 500000;
const int cha = 26;
int n, m, k;
struct Tire{
int next[maxa][cha], fail[maxa], end[maxa];
int root, L;
int newnode(){
for(int i = 0; i < cha; i++){
next[L][i] = -1;
}
end[L++] = 0;
return L-1;
}
void init(){
L = 0;
root = newnode();
}
void insert(char buf[]){
int len = strlen(buf);
int now = root;
for(int i = 0; i < len; i++){
if(next[now][buf[i] - 'a'] == -1)
next[now][buf[i]-'a'] = newnode();
now = next[now][buf[i]-'a'];
//printf("%d ", now);
}//puts("");
end[now] ++;
}
void build(){
queue<int>Q;
fail[root] = root;
for(int i = 0; i < cha; i++){
if(next[root][i] == -1)
next[root][i] = root;
else{
fail[next[root][i]] = root;
Q.push(next[root][i]);
}
}
while(!Q.empty()){
int now = Q.front();
Q.pop();
// end[now] |= end[fail[now]];
for(int i = 0; i < cha; i++){
if(next[now][i] == -1)
next[now][i] = next[fail[now]][i];
else{
fail[next[now][i]] = next[fail[now]][i];
Q.push(next[now][i]);
// printf("**%d %d
",next[now][i],next[fail[now]][i]);
}
}
}
}
int solve(char *s){
int ans = 0, k = 0;
for(int i = 0; s[i]; i++){
int t = s[i] - 'a';
k = next[k][t];
int j = k;
while(j){
ans += end[j];
//if(end[j]) printf("%d ",j);
end[j] = 0;
j = fail[j];
}//puts("");
}
return ans;
}
};
char buf[1000005];
Tire ac;
int main(){
int t, n;
scanf("%d", &t);
while(t--){
scanf("%d", &n);
ac.init();
//memset(ac.end, 0, sizeof(ac.end));
for(int i = 0; i < n; i++){
scanf("%s", buf);
ac.insert(buf);
}
ac.build();
scanf("%s", buf);
printf("%d
", ac.solve(buf));
}
}
/*
abcdefg
bcdefg
cdef
de
e
ssaabcdefg
*/