• 040_面向对象_13_Object类用法


    一、Object类  

      Object类是所有Java类的根基类
      如果在类的声明中未使用extends关键字指明其基类,则默认基类为Object类  

    public class Person {
            ...
    }

    等价于:

    public class Person extends Object {
    ...
    }

    二、toString方法

    toString()的源码:  

        /**
         * Returns a string representation of the object. In general, the
         * {@code toString} method returns a string that
         * "textually represents" this object. The result should
         * be a concise but informative representation that is easy for a
         * person to read.
         * It is recommended that all subclasses override this method.
         * <p>
         * The {@code toString} method for class {@code Object}
         * returns a string consisting of the name of the class of which the
         * object is an instance, the at-sign character `{@code @}', and
         * the unsigned hexadecimal representation of the hash code of the
         * object. In other words, this method returns a string equal to the
         * value of:
         * <blockquote>
         * <pre>
         * getClass().getName() + '@' + Integer.toHexString(hashCode())
         * </pre></blockquote>
         *
         * @return  a string representation of the object.
         */
        public String toString() {
            return getClass().getName() + "@" + Integer.toHexString(hashCode());
        }

      Object类中定义有public String toString()方法,其返回值是 String 类型,描述当前对象的有关信息。
      在打印某个对象时将自动调用该对象类中的 toString()方法。比如:  

    Object object=new Object();
    System.out.println(object);

    结果截图为:

      

      重写toString()、如String类就重写了toString()方法,其重写的源码如下:  

    /**
         * This object (which is already a string!) is itself returned.
         *
         * @return  the string itself.
         */
        public String toString() {
            return this;
        }

      当然我们也可以根据我们自己的需求去重写、此处不做实现。

    三、equals()方法 

      equals()方法提供定义比较两个对象是否“相等”的逻辑。

      Object类中 的 equals 方法 定义为:x.equals ( y ) 当 x 和 y是同一个对象(地址一样)的应用时返回 true 否则返回 false、其源码如下:  

    /**
         * Indicates whether some other object is "equal to" this one.
         * <p>
         * The {@code equals} method implements an equivalence relation
         * on non-null object references:
         * <ul>
         * <li>It is <i>reflexive</i>: for any non-null reference value
         *     {@code x}, {@code x.equals(x)} should return
         *     {@code true}.
         * <li>It is <i>symmetric</i>: for any non-null reference values
         *     {@code x} and {@code y}, {@code x.equals(y)}
         *     should return {@code true} if and only if
         *     {@code y.equals(x)} returns {@code true}.
         * <li>It is <i>transitive</i>: for any non-null reference values
         *     {@code x}, {@code y}, and {@code z}, if
         *     {@code x.equals(y)} returns {@code true} and
         *     {@code y.equals(z)} returns {@code true}, then
         *     {@code x.equals(z)} should return {@code true}.
         * <li>It is <i>consistent</i>: for any non-null reference values
         *     {@code x} and {@code y}, multiple invocations of
         *     {@code x.equals(y)} consistently return {@code true}
         *     or consistently return {@code false}, provided no
         *     information used in {@code equals} comparisons on the
         *     objects is modified.
         * <li>For any non-null reference value {@code x},
         *     {@code x.equals(null)} should return {@code false}.
         * </ul>
         * <p>
         * The {@code equals} method for class {@code Object} implements
         * the most discriminating possible equivalence relation on objects;
         * that is, for any non-null reference values {@code x} and
         * {@code y}, this method returns {@code true} if and only
         * if {@code x} and {@code y} refer to the same object
         * ({@code x == y} has the value {@code true}).
         * <p>
         * Note that it is generally necessary to override the {@code hashCode}
         * method whenever this method is overridden, so as to maintain the
         * general contract for the {@code hashCode} method, which states
         * that equal objects must have equal hash codes.
         *
         * @param   obj   the reference object with which to compare.
         * @return  {@code true} if this object is the same as the obj
         *          argument; {@code false} otherwise.
         * @see     #hashCode()
         * @see     java.util.HashMap
         */
        public boolean equals(Object obj) {
            return (this == obj);
        }

      jdk中提供的一些类,如String,Date等,重写了Object中的equals方法,调用这些类的equals方法, x.equals (y) ,当x和y所引用的对象是同一类对象且属性内容相等时(并不一定是相同对象),返回 true 否则返回 false。

      比如,String类的equals方法显然是比较数组中的char值是否相等,源代码如下:  

     /**
         * Compares this string to the specified object.  The result is {@code
         * true} if and only if the argument is not {@code null} and is a {@code
         * String} object that represents the same sequence of characters as this
         * object.
         *
         * @param  anObject
         *         The object to compare this {@code String} against
         *
         * @return  {@code true} if the given object represents a {@code String}
         *          equivalent to this string, {@code false} otherwise
         *
         * @see  #compareTo(String)
         * @see  #equalsIgnoreCase(String)
         */
        public boolean equals(Object anObject) {
            if (this == anObject) {
                return true;
            }
            if (anObject instanceof String) {
                String anotherString = (String) anObject;
                int n = value.length;
                if (n == anotherString.value.length) {
                    char v1[] = value;
                    char v2[] = anotherString.value;
                    int i = 0;
                    while (n-- != 0) {
                        if (v1[i] != v2[i])
                                return false;
                        i++;
                    }
                    return true;
                }
            }
            return false;
        }

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  • 原文地址:https://www.cnblogs.com/aeon/p/9963570.html
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