• POJ 3461 Oulipo(KMP字符串匹配)


    题意  给你两个字符串p和s  求p在s中出现的次数  很裸的kmp

    因为不止匹配一次  每次找到后还要循环j=next[j]的过程   知道到达s的终点

    #include<cstdio>
    #include<cstring>
    using namespace std;
    const int N = 10005, M = 1000005;
    int next[N], ans, n;
    char p[N], s[M];
    
    void kmp ()
    {
        int lp = strlen (p), ls = strlen (s), i, j;
        next[0] = -1, next[1] = i = 0;
        while ( (++i) < lp)
        {
            j = next[i];
            while (j != -1 && p[i] != p[j])
                j = next[j];
            next[i + 1] = j + 1;
        }
    
        i = j = 0;
        while (i < ls)
        {
            if (j == -1 || s[i] == p[j])
            {
                ++i, ++j;
                if (j == lp) ++ans, j = next[j];
            }
            else j = next[j];
        }
    }
    
    int main()
    {
        scanf ("%d", &n);
        while (n--)
        {
            ans = 0;
            scanf ("%s%s", p, s);
            kmp ();
            printf ("%d
    ", ans);
        }
        return 0;
    }
    

    Oulipo

    Description

    The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from the book:

    Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain, l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait au roman : stir son tapis, assaillant à tout instant son imagination, l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la raison : tout avait l’air normal mais…

    Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive 'T's is not unusual. And they never use spaces.

    So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {'A''B''C', …, 'Z'} and two finite strings over that alphabet, a word W and a text T, count the number of occurrences of W in T. All the consecutive characters of W must exactly match consecutive characters of T. Occurrences may overlap.

    Input

    The first line of the input file contains a single number: the number of test cases to follow. Each test case has the following format:

    • One line with the word W, a string over {'A''B''C', …, 'Z'}, with 1 ≤ |W| ≤ 10,000 (here |W| denotes the length of the string W).
    • One line with the text T, a string over {'A''B''C', …, 'Z'}, with |W| ≤ |T| ≤ 1,000,000.

    Output

    For every test case in the input file, the output should contain a single number, on a single line: the number of occurrences of the word W in the text T.

    Sample Input

    3
    BAPC
    BAPC
    AZA
    AZAZAZA
    VERDI
    AVERDXIVYERDIAN

    Sample Output

    1
    3
    0


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  • 原文地址:https://www.cnblogs.com/acvay/p/3947282.html
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