先对输入排序,然后从前到后判断即可
今天刚学了java的lambda,正好拿来练练手,写起来确实爽。
class Solution {
public List<Interval> merge(List<Interval> intervals) {
if (intervals.size() <= 1) {
return intervals;
}
intervals.sort((e1, e2) -> {
if (e1.start == e2.start) {
return Integer.compare(e1.end, e2.end);
}
return Integer.compare(e1.start, e2.start);
});
List<Interval> ans = new ArrayList<>();
for (int i = 0; i < intervals.size(); i++) {
Interval cur = intervals.get(i);
while (i + 1 < intervals.size()) {
Interval next = intervals.get(i + 1);
if (cur.end >= next.start) {
cur.end = Math.max(cur.end, next.end);
i++;
} else {
break;
}
}
ans.add(cur);
}
return ans;
}
}