这题时间要求比较严格。。。
首先,将piles排序,然后二分查找。
总之,答案K肯定位于piles[?]piles[?+1]或者1piles[0]之间
所以我们先二分把?找到,然后再二分找到K即可
class Solution {
public int minEatingSpeed(int[] piles, int H) {
Arrays.sort(piles);
if (H == piles.length) {
return piles[piles.length - 1];
}
int left = 0;
int right = piles.length - 1;
int mid = (left + right) / 2;
int midK = fun(piles, piles[mid]);
while (right - left > 1) {
if (midK < H) {
right = mid;
} else {
left = mid;
}
mid = (left + right) / 2;
midK = fun(piles, piles[mid]);
}
int ans = piles[left];
if (left == 0) {
ans = 1;
}
int ansLeft = ans;
int ansRight = piles[right];
int ansMid = (ansLeft + ansRight) / 2;
while (ansLeft < ansRight) {
if (!ok(piles, ansMid, H)) {
ansLeft = ansMid + 1;
} else {
ansRight = ansMid;
}
ansMid = (ansLeft + ansRight) / 2;
}
return ansLeft;
}
int fun(int[] piles, int k) {
int ans = 0;
for (int pile : piles) {
ans += pile / k;
if (pile % k > 0) {
ans++;
}
}
return ans;
}
boolean ok(int[] piles, int k, int H) {
long ans = 0;
for (int pile : piles) {
ans += pile / k;
if (pile % k > 0) {
ans++;
}
if (ans > H) {
return false;
}
if (ans < 0) {
return false;
}
}
return true;
}
}