题目要求用O(logn),明显要用二分。
其实二分不难,难的是要处理好边界
class Solution {
public int[] searchRange(int[] nums, int target) {
int i = 0, j = nums.length;
int mid = (i + j) / 2;
int p = -1;
while (i < j) {
if (nums[mid] == target) {
p = mid;
break;
}
if (nums[mid] > target) {
if (j == mid) break;
j = mid;
mid = (i + j) / 2;
} else {
if (i == mid) break;
i = mid;
mid = (i + j) / 2;
}
}
if (p == -1) {
return new int[]{-1, -1};
} else {
int a = p, b = p;
while (a > 0 && nums[a - 1] == target) a--;
while (b < nums.length - 1 && nums[b + 1] == target) b++;
return new int[]{a, b};
}
}
}