• 边工作边刷题:70天一遍leetcode: day 45


    Flatten Nested List Iterator

    要点:题的本质是建立next和isInteger/getList/getInteger的关系,考点和tree的遍历类似:用stack存dfs的trace,这样可以backtrack到之前层的结点。

    • 注意NestedInteger类的表示,清楚了表示很多题就迎刃而解了:NestedInteger表示一个结点:既可以是List也可以是Integer。什么类型由interface的get method返回值决定。而最外层object是List,这样表示不可能以Integer为起点
    • 为什么需要stack?本质上是tree的结构:遍历的时候如果当前元素是list,那么之后要,向更深遍历,并且要能返回的上层继续下一个元素。
    • 如何unwind?对于list,相当于子树展开,这里就把list中元素反向push到stack里。因为list可能为空,这样就没有下一个元素可以iterate,所以要多层展开(也就是说,stack top是不能为list的)直到一个integer元素或者没有其他可遍历元素为止。因此,在init和next得到当前元素后,要用prepare来展开stack top的可能list
    # """
    # This is the interface that allows for creating nested lists.
    # You should not implement it, or speculate about its implementation
    # """
    #class NestedInteger(object):
    #    def isInteger(self):
    #        """
    #        @return True if this NestedInteger holds a single integer, rather than a nested list.
    #        :rtype bool
    #        """
    #
    #    def getInteger(self):
    #        """
    #        @return the single integer that this NestedInteger holds, if it holds a single integer
    #        Return None if this NestedInteger holds a nested list
    #        :rtype int
    #        """
    #
    #    def getList(self):
    #        """
    #        @return the nested list that this NestedInteger holds, if it holds a nested list
    #        Return None if this NestedInteger holds a single integer
    #        :rtype List[NestedInteger]
    #        """
    
    class NestedIterator(object):
    
        def __init__(self, nestedList):
            """
            Initialize your data structure here.
            :type nestedList: List[NestedInteger]
            """
            self.stk = []
            for i in xrange(len(nestedList)-1, -1, -1):
                self.stk.append(nestedList[i])
            self._prepare()
            
        def _prepare(self):
            while self.stk and not self.stk[-1].isInteger():
                topList = self.stk.pop().getList()
                for i in xrange(len(topList)-1, -1, -1):
                    self.stk.append(topList[i])
    
        def next(self):
            """
            :rtype: int
            """
            topInt = self.stk.pop().getInteger()
            self._prepare()
            return topInt
    
        def hasNext(self):
            """
            :rtype: bool
            """
            return self.stk
            
    
    # Your NestedIterator object will be instantiated and called as such:
    # i, v = NestedIterator(nestedList), []
    # while i.hasNext(): v.append(i.next())
    
    
  • 相关阅读:
    async 和 await
    Nginx配置反向代理与负载均衡
    简单使用高德地图开放平台API
    layui select 动态赋值
    ERROR: Pool overlaps with other one on this address space
    解决docker镜像无法删除的问题
    伪静态问题导致前台页面无法通过地址栏访问
    ERROR: Failed to Setup IP tables: Unable to enable SKIP DNAT rule
    PHP使用引用实现无限极分类
    composer update -- memory_limit
  • 原文地址:https://www.cnblogs.com/absolute/p/5690304.html
Copyright © 2020-2023  润新知