• js比较两个单独的数组或对象是否相等


    所谓js的中的传值,其实也就是说5种基本数据类型(null,undefind,boolean,number,string)

    传引用也就是说的那个引用数据类型,(array和object)

    基本数据类型的值不可变,而引用数据类型的值是可变的

    所以当你比较数组和对象时,都是false;除非你是克隆的原份数据

    即: var a = { name: "李四" }; var b = a;

    大家通常称对象为引用类型,以此来和基本类型进行区分; 而对象值都是引用,所以的对象的比较也叫引用的比较,当且当他们都指向同一个引用时,即都引用的同一个基对象时,它们才相等.

    1.比较两个单独的数组是否相等

    JSON.stringify(a1) == JSON.stringify(a2)

    a1.toString() == a2.toString()

    要判断2个数组是否相同,把数组转换成字符串进行比较。

    如果要比较两个数组的元素是否相等,则:

    JSON.stringify([1,2,3].sort()) === JSON.stringify([3,2,1].sort());

    [1,2,3].sort().toString() === [3,2,1].sort().toString();

    判断2个数组是否相同,首先要把数组进行排序,然后转换成字符串进行比较。

    2.比较两个单独的对象是否相等

    let cmp = ( x, y ) => {
    // If both x and y are null or undefined and exactly the same
        if ( x === y ) {
          return true;
        }
    // If they are not strictly equal, they both need to be Objects
        if ( ! ( x instanceof Object ) || ! ( y instanceof Object ) ) {
          return false;
        }
    //They must have the exact same prototype chain,the closest we can do is
    //test the constructor.
        if ( x.constructor !== y.constructor ) {
          return false;
        }
        for ( var p in x ) {
          //Inherited properties were tested using x.constructor === y.constructor
          if ( x.hasOwnProperty( p ) ) {
            // Allows comparing x[ p ] and y[ p ] when set to undefined
            if ( ! y.hasOwnProperty( p ) ) {
              return false;
            }
            // If they have the same strict value or identity then they are equal
            if ( x[ p ] === y[ p ] ) {
              continue;
            }
            // Numbers, Strings, Functions, Booleans must be strictly equal
            if ( typeof( x[ p ] ) !== "object" ) {
              return false;
            }
            // Objects and Arrays must be tested recursively
            if ( ! Object.equals( x[ p ], y[ p ] ) ) {
              return false;
            }
          }
        }
        for ( p in y ) {
          // allows x[ p ] to be set to undefined
          if ( y.hasOwnProperty( p ) && ! x.hasOwnProperty( p ) ) {
            return false;
          }
        }
        return true;
    };

    下面是StackOverflow大神封装的方法,可以学习一下:

    1.比较数组

    // Warn if overriding existing method
    if(Array.prototype.equals)
        console.warn("Overriding existing Array.prototype.equals. Possible causes: New API defines the method, there's a framework conflict or you've got double inclusions in your code.");
    // attach the .equals method to Array's prototype to call it on any array
    Array.prototype.equals = function (array) {
        // if the other array is a falsy value, return
        if (!array)
            return false;
    
        // compare lengths - can save a lot of time 
        if (this.length != array.length)
            return false;
    
        for (var i = 0, l = this.length; i < l; i++) {
            // Check if we have nested arrays
            if (this[i] instanceof Array && array[i] instanceof Array) {
                // recurse into the nested arrays
                if (!this[i].equals(array[i]))
                    return false;       
            }           
            else if (this[i] != array[i]) { 
                // Warning - two different object instances will never be equal: {x:20} != {x:20}
                return false;   
            }           
        }       
        return true;
    }
    // Hide method from for-in loops
    Object.defineProperty(Array.prototype, "equals", {enumerable: false});

    2.比较对象

    Object.prototype.equals = function(object2) {
        //For the first loop, we only check for types
        for (propName in this) {
            //Check for inherited methods and properties - like .equals itself
            //https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Object/hasOwnProperty
            //Return false if the return value is different
            if (this.hasOwnProperty(propName) != object2.hasOwnProperty(propName)) {
                return false;
            }
            //Check instance type
            else if (typeof this[propName] != typeof object2[propName]) {
                //Different types => not equal
                return false;
            }
        }
        //Now a deeper check using other objects property names
        for(propName in object2) {
            //We must check instances anyway, there may be a property that only exists in object2
                //I wonder, if remembering the checked values from the first loop would be faster or not 
            if (this.hasOwnProperty(propName) != object2.hasOwnProperty(propName)) {
                return false;
            }
            else if (typeof this[propName] != typeof object2[propName]) {
                return false;
            }
            //If the property is inherited, do not check any more (it must be equa if both objects inherit it)
            if(!this.hasOwnProperty(propName))
              continue;
    
            //Now the detail check and recursion
    
            //This returns the script back to the array comparing
            /**REQUIRES Array.equals**/
            if (this[propName] instanceof Array && object2[propName] instanceof Array) {
                       // recurse into the nested arrays
               if (!this[propName].equals(object2[propName]))
                            return false;
            }
            else if (this[propName] instanceof Object && object2[propName] instanceof Object) {
                       // recurse into another objects
                       //console.log("Recursing to compare ", this[propName],"with",object2[propName], " both named ""+propName+""");
               if (!this[propName].equals(object2[propName]))
                            return false;
            }
            //Normal value comparison for strings and numbers
            else if(this[propName] != object2[propName]) {
               return false;
            }
        }
        //If everything passed, let's say YES
        return true;
    }
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  • 原文地址:https://www.cnblogs.com/abc-x/p/10780464.html
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