590. N叉树的后序遍历
给定一个 N 叉树,返回其节点值的后序遍历。
例如,给定一个 3叉树 :
返回其后序遍历: [5,6,3,2,4,1].
说明: 递归法很简单,你可以使用迭代法完成此题吗?
/*
// Definition for a Node.
class Node {
public int val;
public List<Node> children;
public Node() {}
public Node(int _val) {
val = _val;
}
public Node(int _val, List<Node> _children) {
val = _val;
children = _children;
}
};
*/
class Solution {
public List<Integer> postorder(Node root) {
LinkedList<Integer> output = new LinkedList<>();
if (root == null) {
return output;
}
Deque<Node> stack = new LinkedList<>();
stack.add(root);
while (!stack.isEmpty()) {
Node curNode = stack.pollLast();
output.addFirst(curNode.val);
if (curNode.children != null && !curNode.children.isEmpty()) {
stack.addAll(curNode.children);
}
}
return output;
}
}