• BZOJ 1934: [Shoi2007]Vote 善意的投票


    二次联通门 : BZOJ 1934: [Shoi2007]Vote 善意的投票

    /*
        BZOJ 1934: [Shoi2007]Vote 善意的投票
    
        最小割
    
    */
    #include <cstdio>
    #include <iostream>
    #define rg register
    
    inline void read (int &n) { 
        rg char c = getchar ();
        for (n = 0; !isdigit (c); c = getchar ());
        for (; isdigit (c); n = n * 10 + c - '0', c = getchar ());
    }
    #define Max 900
    int S, T;
    #define INF 1e9
    namespace net {
    
        const int MaxE = 200005;
        int _n[MaxE], _v[MaxE], list[Max], _f[MaxE], EC = 1, d[Max], q[Max], tc[Max];
        
        inline void In (int u, int v, int f) { 
            _v[++ EC] = v, _n[EC] = list[u], list[u] = EC, _f[EC] = f;
            _v[++ EC] = u, _n[EC] = list[v], list[v] = EC, _f[EC] = 0;
        }
    
        bool Bfs () {
            int h = 1, t = 1; q[t] = S; rg int i, n;
            for (i = 0; i <= T; ++ i) d[i] = -1;
            for (d[S] = 0; h <= t; ++ h)
                for (n = q[h], i = list[n]; i; i = _n[i])
                    if (_f[i] && d[_v[i]] < 0) {
                        d[_v[i]] = d[n] + 1, q[++ t] = _v[i];
                        if (_v[i] == T) return true; 
                    }
            return false;
        }
        int Flowing (int n, int f) {
            if (n == T || f == 0) return f;
            int p, r = 0;
            for (rg int &i = tc[n]; i; i = _n[i])
                if (_f[i] && d[_v[i]] == d[n] + 1) {
                    p = Flowing (_v[i], std :: min (_f[i], f));
                    if (p > 0) { 
                        r += p, f -= p, _f[i] -= p, _f[i ^ 1] += p;
                        if (f == 0) return r;
                    }
                }
            if (r != f) d[n] = -1; return r;
        }
    
        int Dinic () { 
            int res = 0;
            for (; Bfs (); res += Flowing (S, INF))
                for (rg int i = 0; i <= T; ++ i) tc[i] = list[i];
            return res;
        }
    }
    
    int main (int argc, char *argv[]) {
        int x, y, N, M; read (N), read (M); S = 0, T = N + 1; rg int i;
        for (i = 1; i <= N; ++ i) {
            read (x);
            if (x) net :: In (S, i, 1), net :: In (i, T, 0);
            else net :: In (S, i, 0), net :: In (i, T, 1);
        }
        for (i = 1; i <= M; ++ i) read (x), read (y), net :: In (x, y, 1), net :: In (y, x, 1);
        printf ("%d", net :: Dinic ());
        
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/ZlycerQan/p/8318732.html
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