• codevs 1422 河城荷取


    二次联通门 : codevs 1422 河城荷取

    /*
        codevs 1422 河城荷取
        
        二分费用
        
        重新构图
        最大流判断是否可行
        
        用了邻接矩阵来存初始的流量和费用。。。
        慢的要死
         
    */
    #include <cstring>
    #include <cstdio>
    #include <queue>
    
    #define Max 2003
    #define INF 1e9
    
    void read (int &now)
    {
        register char word = getchar ();
        for (now = 0; word < '0' || word > '9'; word = getchar ());
        for (; word >= '0' && word <= '9'; now = now * 10 + word - '0', word = getchar ());
    }
    
    
    int N, M, L, K;
    
    int can_flow[Max][Max];
    int cost[Max][Max];
    
    inline int max (int &a, int &b)
    {
        return a > b ? a : b;
    }
    
    inline int min (int &a, int &b)
    {
        return a < b ? a : b;
    }
    int T;
    const int S = 0;
    
    class Net_Flow_Type
    {
            
        private :
            
            int __to[Max * Max], __next[Max * Max];
            int __flow[Max * Max];
            
            int Edge_Count;
            int edge_list[Max];
            int deep[Max];
            
            int __tech_[Max];
            
        public :
                    
            inline void Clear ()
            {
                Edge_Count = 1;
                memset (edge_list, 0, sizeof edge_list);
            }
            
            inline void Insert_edge (int from, int to, int key)
            {
                Edge_Count ++;
                __to[Edge_Count] = to;
                __next[Edge_Count] = edge_list[from];
                edge_list[from] = Edge_Count;
                __flow[Edge_Count] = key;
                
                Edge_Count ++;
                __to[Edge_Count] = from;
                __next[Edge_Count] = edge_list[to];
                edge_list[to] = Edge_Count;
                __flow[Edge_Count] = 0;
            }
            
            bool Bfs ()
            {
                std :: queue <int> Queue;
                memset (deep, -1, sizeof deep);
                deep[S] = 0;
                register int now;
                for (Queue.push (S); !Queue.empty (); Queue.pop ())
                {
                    now = Queue.front ();
                    register int i;
                    for (i = edge_list[now]; i; i = __next[i])
                        if (deep[__to[i]] < 0 && __flow[i])
                        {
                            deep[__to[i]] = deep[now] + 1;
                            if (__to[i] == T)
                                return true;
                            Queue.push (__to[i]); 
                        }
                }
                return deep[T] != -1;
            }
            
            int Flowing (int now, int flow)
            {
                if (now == T || flow == 0)
                    return flow;
                int res, last = 0;
                
                for (int &i = __tech_[now]; i; i = __next[i])
                {
                    if (deep[__to[i]] != deep[now] + 1 || __flow[i] == 0)
                        continue;
                    res = Flowing (__to[i], min (flow, __flow[i]));
                    if (res > 0)
                    {
                        last += res;
                        flow -= res;
                        __flow[i] -= res;
                        __flow[i ^ 1] += res;
                        if (flow == 0)
                            return last;
                    }
                }
                if (flow != last)
                    deep[now] = -1;
                return last;
            }
            
            int Dinic ()
            {
                int Answer = 0;
                while (Bfs ())
                {
                    memcpy ( __tech_,edge_list, sizeof edge_list);
                    Answer += Flowing (S, INF);
                }
                return Answer;
            }
    };
    
    Net_Flow_Type Flow;
    
    bool Judge (int key)
    {
        Flow.Clear ();
        for (register int i = 1; i <= L; i ++)
            Flow.Insert_edge (S, i, INF);
            
        for (register int i = 1, j; i <= N; i ++)
            for (j = 1; j <= N; j ++)
            {
                if (i == j)
                    continue;
                if (cost[i][j] <= key)
                    Flow.Insert_edge (i, j, can_flow[i][j]);
            }
        
        Flow.Insert_edge (N, T, INF);
        
        return Flow.Dinic () >= K;
    }
    
    int Answer;
    
    int main (int argc, char *argv[])
    {
        read (N);
        read (M);
        read (L);
        read (K);
        
        T = N + 1;
        int l = 0, r = -INF, Mid;
        
        memset (cost, 0x3f, sizeof cost);
        int x, y, z, s;
        for (register int i = 1; i <= M; i ++)
        {
            read (x);
            read (y);
            read (z);
            read (s);
            
            can_flow[x][y] = z;
            cost[x][y] = s;
            r = max (r, s);
        }
        
        for (; l <= r; )
        {
            Mid = l + r >> 1;
            if (Judge (Mid))
            {
                r = Mid - 1;
                Answer = Mid;
            }
            else
                l = Mid + 1;
        }
        
        printf ("%d", Answer);
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/ZlycerQan/p/7209483.html
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