• BZOJ 2049: [Sdoi2008]Cave 洞穴勘测


    二次联通门 : BZOJ 2049: [Sdoi2008]Cave 洞穴勘测

    其实指针也不是很慢

    我的指针代码能吊打70%的数组

    及80%的指针。。。。

    /*
        BZOJ 2049: [Sdoi2008]Cave 洞穴勘测
        
        LCT
        
        连边
        删边
        
        查询是否在同一树中时, 只需要一直向上跳
        看看树根是否相同就好了 
    */
    #include <cstdio>
    #include <cstdlib>
    #include <iostream>
    
    #define Max 400009
    
    int N;
    
    void read (int &now)
    {
        now = 0;
        register char word = getchar ();
        while (word < '0' || word > '9')
            word = getchar ();
        while (word >= '0' && word <= '9')
        {
            now = now * 10 + word - '0';
            word = getchar ();
        }
    }
    
    inline int min (int a, int b)
    {
        return a < b ? a : b;
    }
    
    struct Splay_Tree_Data
    {
        Splay_Tree_Data *child[2];
        Splay_Tree_Data *father;
    
        int Flandre;
    
        Splay_Tree_Data ()
        {
            Flandre = 0;
            father = NULL;
            child[0] = child[1] = NULL;
        }
    
        inline void Down ()
        {
            if (!Flandre)
                return ;
            std :: swap (child[0], child[1]);
            Flandre = 0;
            if (child[0])
                child[0]->Flandre ^= 1;
            if (child[1])
                child[1]->Flandre ^= 1;
        }
    
        inline int Get_Pos ()
        {
            return this->father->child[1] == this;
        }
    
        inline int Is_Root ()
        {
            return !(this->father) || (this->father->child[0] != this && this->father->child[1] != this);
        }
    };
    
    Splay_Tree_Data *data[Max];
    Splay_Tree_Data *node[Max];
    
    class Link_Cut_Tree_Type
    {
        private :
            
            inline void Rotate (Splay_Tree_Data *now)
            {
                int pos = now->Get_Pos () ^ 1;
                Splay_Tree_Data *Father = now->father;
                Father->child[pos ^ 1] = now->child[pos];
                if (now->child[pos])
                    now->child[pos]->father = Father;
                now->father = Father->father;
                if (!(Father->Is_Root ()))
                    now->father->child[Father->Get_Pos ()] = now;
                Father->father = now;
                now->child[pos] = Father;
            }
    
            inline void Splay (Splay_Tree_Data *now)
            {
                int Count = 0;
                for (Splay_Tree_Data *Father = now; ; Father = Father->father)
                {
                    data[++Count] = Father;
                     if (Father->Is_Root ())
                        break;
                }
                for (; Count >= 1; -- Count)
                    data[Count]->Down ();
                for (; !(now->Is_Root ()); Rotate (now))
                    if (!(now->father->Is_Root ()))
                        Rotate (now->Get_Pos () == now->father->Get_Pos () ? now->father : now);
            }
    
            inline void Access (Splay_Tree_Data *now)
            {
                for (Splay_Tree_Data *Father = NULL; now; Father = now, now = now->father)
                {
                    Splay (now);
                    now->child[1] = Father;
                }
            }
    
            inline void Make_Root (Splay_Tree_Data *now)
            {
                Access (now);
                Splay (now);
                now->Flandre ^= 1;
            }
    
    
        public :
    
            inline void Cut (Splay_Tree_Data *x, Splay_Tree_Data *y)
            {
                Make_Root (x);
                Access (y);
                Splay (y);
                x->father = y->child[0] = NULL;
            }
    
            inline void Link (Splay_Tree_Data *x, Splay_Tree_Data *y)
            {
                Make_Root (x);
                x->father = y;
            }
            
            int Query (Splay_Tree_Data *x, Splay_Tree_Data *y)
            {
                while (x->father)
                    x = x->father;
                while (y->father)
                    y = y->father;
                return x == y;
            }
    };
    
    Link_Cut_Tree_Type Make;
    
    int main (int argc, char *argv[])
    {
        read (N);
        
        char type[10];
        int x, y;
        int M;
        for (int i = 0; i <= N; i ++)
            node[i] = new Splay_Tree_Data;
        for (read (M); M--; )
        {
            scanf ("%s", type);
            read (x);
            read (y);
            if (type[0] == 'Q')
                printf (Make.Query (node[x], node[y]) ? "Yes
    " : "No
    ");
            else if (type[0] == 'C')
                Make.Link (node[x], node[y]);
            else 
                Make.Cut (node[x], node[y]); 
        }
        return 0;
    }
  • 相关阅读:
    2D单人姿态估计论文及代码地址
    pytorch-stacked-hourglass
    stacked-hourglass-networks
    Android ViewBadger
    Stacked Hourglass Networks in Pytorch
    BurstCamera
    Android camera library for taking multiple photos
    TakePhoto android
    PyTorch Tutorial
    LiveNVR传统安防摄像机互联网直播-二次开发相关的API接口
  • 原文地址:https://www.cnblogs.com/ZlycerQan/p/6964459.html
Copyright © 2020-2023  润新知