Lake Counting
Time Limit: 1000MS | Memory Limit: 65536K | |
Total Submissions: 16802 | Accepted: 8523 |
Description
Due to recent rains, water has pooled in various places in Farmer John's field, which is represented by a rectangle of N x M (1 <= N <= 100; 1 <= M <= 100) squares. Each square contains either water ('W') or dry land ('.'). Farmer John would like to figure
out how many ponds have formed in his field. A pond is a connected set of squares with water in them, where a square is considered adjacent to all eight of its neighbors.
Given a diagram of Farmer John's field, determine how many ponds he has.
Given a diagram of Farmer John's field, determine how many ponds he has.
Input
* Line 1: Two space-separated integers: N and M
* Lines 2..N+1: M characters per line representing one row of Farmer John's field. Each character is either 'W' or '.'. The characters do not have spaces between them.
* Lines 2..N+1: M characters per line representing one row of Farmer John's field. Each character is either 'W' or '.'. The characters do not have spaces between them.
Output
* Line 1: The number of ponds in Farmer John's field.
Sample Input
10 12 W........WW. .WWW.....WWW ....WW...WW. .........WW. .........W.. ..W......W.. .W.W.....WW. W.W.W.....W. .W.W......W. ..W.......W.
Sample Output
3
题目如上:
AC代码如下:
#include<iostream> #include<stdio.h> #define Max 105 using namespace std; char f[Max][Max]; int N ,M; void DFS(int x,int y) { f[x][y] = '.'; for(int dx = -1; dx <= 1; dx++) for(int dy = -1; dy <= 1; dy++) { int nx, ny; nx = x + dx; ny = y + dy; if(nx < N&& ny < M&& nx >= 0&& ny >= 0&&f[nx][ny] == 'W') DFS(nx,ny); } return ; } int main() { int res = 0,i,j; cin>>N; cin>>M; for(i = 0; i < N; i++) scanf("%s",&f[i]); for(int i = 0; i < N; i++) for(int j = 0; j < M; j++) if(f[i][j] == 'W') { DFS(i,j); res++; } printf("%d ",res); }
【存在的问题】1、脑残地把坐标轴坐标和矩阵的坐标对应起来了;
2、解决了以上问题后程序还是在傲娇地RE,原来还是脑残地把“=”敲成“==”了;
再后来程序还傲娇地WA了,于是
3、经大湿的指点把原输入
for(i = 0; i < N; i++)
for(j = 0; j < M; j++)
scanf("%c",&f[i][j]);
换成了
for(i = 0; i < N; i++)
scanf("%s", &f[i]);
蓝后就AC了~~o(≧v≦)o~~
原因就是%c输入把换行符给吃掉了~~蓝后造成了移位。。。。
ORZ。。。。