• [USACO14JAN]记录奥林比克


    题目描述
    Being a fan of all cold-weather sports (especially those involving cows),Farmer John wants to record as much of the upcoming winter Moolympics as possible.
    The television schedule for the Moolympics consists of N different programs(1 <= N <= 150), each with a designated starting time and ending time. FJ has a dual-tuner recorder that can record two programs simultaneously.
    Please help him determine the maximum number of programs he can record in total.

    农民约翰热衷于所有寒冷天气的运动(尤其是涉及到牛的运动), 农民约翰想记录尽可能多的moolympics为即将到来的冬季 可能的。 为moolympics电视时间表由N个不同的程序 (1 < = n=150),每个具有指定的开始时间和结束时间。FJ 有一个双调谐器录音机,可以同时录制两个节目。 请帮助他确定他能录制的节目的最大数量。

    输入输出格式

    输入格式:
    * Line 1: The integer N.
    * Lines 2..1+N: Each line contains the start and end time of a single program (integers in the range 0..1,000,000,000).
    第1行:整数n。 第2行.. 1 + n:每行包含单个的开始和结束时间 程序(范围为0…1000000000的整数)。

    输出格式:
    * Line 1: The maximum number of programs FJ can record.
    仅一行,节目FJ可以记录的最大数量。

    输入输出样例

    输入样例#1:
    6
    0 3
    6 7
    3 10
    1 5
    2 8
    1 9
    输出样例#1:
    4

    说明
    INPUT DETAILS:
    The Moolympics broadcast consists of 6 programs. The first runs from time 0 to time 3, and so on.
    OUTPUT DETAILS:
    FJ can record at most 4 programs. For example, he can record programs 1 and 3 back-to-back on the first tuner, and programs 2 and 4 on the second tuner.
    Source: USACO 2014 January Contest, Silver
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    分析

    用贪心。
    按照结束时间排序。
    若节目可以放.则必定放。
    尽量放在结束时间长的1组。
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    程序:
    var
    a,b:array[0..151] of longint;
    i,j,n,t,t1,s:longint;
    begin
        readln(n);
        for i:=1 to n do
        readln(a[i],b[i]);
        for i:=1 to n-1 do
        for j:=i+1 to n do
        if (b[i]>b[j]) or (b[i]=b[j]) and (a[i]>a[j]) then
        begin
            t:=b[i];b[i]:=b[j];b[j]:=t;
            t:=a[i];a[i]:=a[j];a[j]:=t;
        end;
        t:=0;
        t1:=0;
        s:=0;
        for i:=1 to n do
        if a[i]>=t then
        begin
            inc(s);
            if (t1>=t)and(a[i]>=t1) then t1:=b[i] else t:=b[i];
        end else
        if a[i]>=t1 then
        begin
            inc(s);
            t1:=b[i];
        end;
        writeln(s);
    end.
    
    
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  • 原文地址:https://www.cnblogs.com/YYC-0304/p/9499976.html
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