Given a binary tree, return the postorder traversal of its nodes' values.
For example:
Given binary tree {1,#,2,3}
,
1 2 / 3
return [3,2,1]
.
Note: Recursive solution is trivial, could you do it iteratively?
1 /** 2 * Definition for binary tree 3 * struct TreeNode { 4 * int val; 5 * TreeNode *left; 6 * TreeNode *right; 7 * TreeNode(int x) : val(x), left(NULL), right(NULL) {} 8 * }; 9 */ 10 class Solution { 11 public: 12 vector<int> postorderTraversal(TreeNode *root) { 13 14 vector<int> vec; 15 getVal(vec, root); 16 return vec; 17 } 18 19 void getVal(vector<int> &vec, TreeNode *root) 20 { 21 if(root != NULL) 22 { 23 getVal(vec, root->left); 24 getVal(vec, root->right); 25 vec.push_back(root->val); 26 } 27 } 28 };