• BZOJ 3223 & 区间翻转


    题意:

      就是贴个代码,这是我入门题的弱化版。。然而一共还是写了40分钟,不专注(一边看比赛一边打)是一个问题,splay每个操作的细节确实有点多(什么时候updata啊。。什么时候pushdown啊。。先后顺序啊)。。还是专注一点尽量一次写出,调代码太折磨了。

    CODE:

    /*==========================================================================
    # Last modified: 2016-02-21 19:13
    # Filename: bz3223.cpp
    # Description: 
    ==========================================================================*/
    #define me AcrossTheSky 
    #include <cstdio> 
    #include <cmath> 
    #include <ctime> 
    #include <string> 
    #include <cstring> 
    #include <cstdlib> 
    #include <iostream> 
    #include <algorithm> 
      
    #include <set> 
    #include <map> 
    #include <stack> 
    #include <queue> 
    #include <vector> 
     
    #define lowbit(x) (x)&(-x) 
    #define FOR(i,a,b) for((i)=(a);(i)<=(b);(i)++) 
    #define FORP(i,a,b) for(int i=(a);i<=(b);i++) 
    #define FORM(i,a,b) for(int i=(a);i>=(b);i--) 
    #define ls(a,b) (((a)+(b)) << 1) 
    #define rs(a,b) (((a)+(b)) >> 1) 
    #define getlc(a) ch[(a)][0] 
    #define getrc(a) ch[(a)][1] 
     
    #define maxn 200000 
    #define maxm 100000 
    #define pi 3.1415926535898 
    #define _e 2.718281828459 
    #define INF 1070000000 
    using namespace std; 
    typedef long long ll; 
    typedef unsigned long long ull; 
     
    template<class T> inline 
    void read(T& num) { 
        bool start=false,neg=false; 
        char c; 
        num=0; 
        while((c=getchar())!=EOF) { 
            if(c=='-') start=neg=true; 
            else if(c>='0' && c<='9') { 
                start=true; 
                num=num*10+c-'0'; 
            } else if(start) break; 
        } 
        if(neg) num=-num; 
    } 
    /*==================split line==================*/ 
    int n,m;
    int ch[maxn][2],s[maxn],flip[maxn],fa[maxn];
    int root,null=0;
    
    void updata(int node){s[node]=s[getlc(node)]+s[getrc(node)]+1;}
    void pushdown(int node){
    	if (!flip[node]) return;
    	flip[node]=0;
    	swap(getlc(node),getrc(node));
    	flip[getlc(node)]^=1; flip[getrc(node)]^=1;
    }
    int build(int l,int r){
    	if (l>r) return 0;
    	if (l==r) { s[l]=1;	return l;}
    	int mid=rs(l,r);
    	fa[ch[mid][0]=build(l,mid-1)]=mid; fa[ch[mid][1]=build(mid+1,r)]=mid;
    	updata(mid);
    	return mid;
    }
    void rotate(int x){
    	int p=fa[x],q=fa[p],d=ch[p][1]==x;
    	pushdown(x); pushdown(p);
    	fa[ch[p][d]=ch[x][d^1]]=p; updata(p);
    	fa[ch[x][d^1]=p]=x; updata(x);
    	fa[x]=q;
    	if (q){
    		if (getlc(q)==p) getlc(q)=x;
    		else if (getrc(q)==p) getrc(q)=x;
    		updata(q);
    	}
    }
    void splay(int x,int &aim){
    	for (int y; (y=fa[x])!=aim;rotate(x))
    		if (fa[y]!=aim) rotate((getlc(y)==x)==(getrc(fa[y])==y)?y:x);
    	updata(x);
    	if (aim==0) root=x;
    }
    int kth(int k,int node){
    	int x=node;
    	while(x){
    		pushdown(x);
    		int ss=s[ch[x][0]];
    		if (k==ss+1) return x;
    		if (k<=ss) x=ch[x][0];
    		else x=ch[x][1],k-=ss,k--;
    	}
    }
    void change(int l,int r){
    	int node=kth(l,root); splay(node,null); 
    	node=kth(r+2,root); splay(node,root);
    	flip[getlc(getrc(root))]^=1;
    }
    void print(int node){
    	if(!node) return;
    	pushdown(node);
    	print(getlc(node));
    	if (node!=1 && node!=n+2) printf("%d ",node-1);
    	print(getrc(node));
    }
    int main(){
    	read(n); read(m);
    	memset(flip,0,sizeof(flip));
    	root=build(1,n+2);
    	FORP(i,1,m) {
    		int l,r; read(l); read(r);
    		change(l,r);
    	}
    	print(root);
    }
    
    Sometimes it s the very people who no one imagines anything of. who do the things that no one can imagine.
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  • 原文地址:https://www.cnblogs.com/YCuangWhen/p/5205459.html
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