一 介绍
本节主题
多表连接查询
复合条件连接查询
子查询
准备表
company.employee
company.department
#建表 create table department( id int, name varchar(20) ); create table employee( id int primary key auto_increment, name varchar(20), sex enum('male','female') not null default 'male', age int, dep_id int ); #插入数据 insert into department values (200,'技术'), (201,'人力资源'), (202,'销售'), (203,'运营'); insert into employee(name,sex,age,dep_id) values ('egon','male',18,200), ('alex','female',48,201), ('wupeiqi','male',38,201), ('yuanhao','female',28,202), ('liwenzhou','male',18,200), ('jingliyang','female',18,204) ; #查看表结构和数据 mysql> desc department; +-------+-------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +-------+-------------+------+-----+---------+-------+ | id | int(11) | YES | | NULL | | | name | varchar(20) | YES | | NULL | | +-------+-------------+------+-----+---------+-------+ mysql> desc employee; +--------+-----------------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +--------+-----------------------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | name | varchar(20) | YES | | NULL | | | sex | enum('male','female') | NO | | male | | | age | int(11) | YES | | NULL | | | dep_id | int(11) | YES | | NULL | | +--------+-----------------------+------+-----+---------+----------------+ mysql> select * from department; +------+--------------+ | id | name | +------+--------------+ | 200 | 技术 | | 201 | 人力资源 | | 202 | 销售 | | 203 | 运营 | +------+--------------+ mysql> select * from employee; +----+------------+--------+------+--------+ | id | name | sex | age | dep_id | +----+------------+--------+------+--------+ | 1 | egon | male | 18 | 200 | | 2 | alex | female | 48 | 201 | | 3 | wupeiqi | male | 38 | 201 | | 4 | yuanhao | female | 28 | 202 | | 5 | liwenzhou | male | 18 | 200 | | 6 | jingliyang | female | 18 | 204 | +----+------------+--------+------+--------+
二 多表连接查询
#重点:外链接语法 SELECT 字段列表 FROM 表1 INNER|LEFT|RIGHT JOIN 表2 ON 表1.字段 = 表2.字段;
1 交叉连接:不适用任何匹配条件。生成笛卡尔积
mysql> select * from employee,department; +----+------------+--------+------+--------+------+--------------+ | id | name | sex | age | dep_id | id | name | +----+------------+--------+------+--------+------+--------------+ | 1 | egon | male | 18 | 200 | 200 | 技术 | | 1 | egon | male | 18 | 200 | 201 | 人力资源 | | 1 | egon | male | 18 | 200 | 202 | 销售 | | 1 | egon | male | 18 | 200 | 203 | 运营 | | 2 | alex | female | 48 | 201 | 200 | 技术 | | 2 | alex | female | 48 | 201 | 201 | 人力资源 | | 2 | alex | female | 48 | 201 | 202 | 销售 | | 2 | alex | female | 48 | 201 | 203 | 运营 | | 3 | wupeiqi | male | 38 | 201 | 200 | 技术 | | 3 | wupeiqi | male | 38 | 201 | 201 | 人力资源 | | 3 | wupeiqi | male | 38 | 201 | 202 | 销售 | | 3 | wupeiqi | male | 38 | 201 | 203 | 运营 | | 4 | yuanhao | female | 28 | 202 | 200 | 技术 | | 4 | yuanhao | female | 28 | 202 | 201 | 人力资源 | | 4 | yuanhao | female | 28 | 202 | 202 | 销售 | | 4 | yuanhao | female | 28 | 202 | 203 | 运营 | | 5 | liwenzhou | male | 18 | 200 | 200 | 技术 | | 5 | liwenzhou | male | 18 | 200 | 201 | 人力资源 | | 5 | liwenzhou | male | 18 | 200 | 202 | 销售 | | 5 | liwenzhou | male | 18 | 200 | 203 | 运营 | | 6 | jingliyang | female | 18 | 204 | 200 | 技术 | | 6 | jingliyang | female | 18 | 204 | 201 | 人力资源 | | 6 | jingliyang | female | 18 | 204 | 202 | 销售 | | 6 | jingliyang | female | 18 | 204 | 203 | 运营 | +----+------------+--------+------+--------+------+--------------+
2 内连接:只连接匹配的行
#找两张表共有的部分,相当于利用条件从笛卡尔积结果中筛选出了正确的结果 #department没有204这个部门,因而employee表中关于204这条员工信息没有匹配出来 mysql> select employee.id,employee.name,employee.age,employee.sex,department.name from employee inner join department on employee.dep_id=department.id; +----+-----------+------+--------+--------------+ | id | name | age | sex | name | +----+-----------+------+--------+--------------+ | 1 | egon | 18 | male | 技术 | | 2 | alex | 48 | female | 人力资源 | | 3 | wupeiqi | 38 | male | 人力资源 | | 4 | yuanhao | 28 | female | 销售 | | 5 | liwenzhou | 18 | male | 技术 | +----+-----------+------+--------+--------------+ #上述sql等同于 mysql> select employee.id,employee.name,employee.age,employee.sex,department.name from employee,department where employee.dep_id=department.id;
3 外链接之左连接:优先显示左表全部记录
#以左表为准,即找出所有员工信息,当然包括没有部门的员工 #本质就是:在内连接的基础上增加左边有右边没有的结果 mysql> select employee.id,employee.name,department.name as depart_name from employee left join department on employee.dep_id=department.id; +----+------------+--------------+ | id | name | depart_name | +----+------------+--------------+ | 1 | egon | 技术 | | 5 | liwenzhou | 技术 | | 2 | alex | 人力资源 | | 3 | wupeiqi | 人力资源 | | 4 | yuanhao | 销售 | | 6 | jingliyang | NULL | +----+------------+--------------+
4 外链接之右连接:优先显示右表全部记录
#以右表为准,即找出所有部门信息,包括没有员工的部门 #本质就是:在内连接的基础上增加右边有左边没有的结果 mysql> select employee.id,employee.name,department.name as depart_name from employee right join department on employee.dep_id=department.id; +------+-----------+--------------+ | id | name | depart_name | +------+-----------+--------------+ | 1 | egon | 技术 | | 2 | alex | 人力资源 | | 3 | wupeiqi | 人力资源 | | 4 | yuanhao | 销售 | | 5 | liwenzhou | 技术 | | NULL | NULL | 运营 | +------+-----------+--------------+
5 全外连接:显示左右两个表全部记录
#注意 union与union all的区别:union会去掉相同的纪录
全外连接:在内连接的基础上增加左边有右边没有的和右边有左边没有的结果 #注意:mysql不支持全外连接 full JOIN #强调:mysql可以使用此种方式间接实现全外连接 select * from employee left join department on employee.dep_id = department.id union select * from employee right join department on employee.dep_id = department.id ; #查看结果 +------+------------+--------+------+--------+------+--------------+ | id | name | sex | age | dep_id | id | name | +------+------------+--------+------+--------+------+--------------+ | 1 | egon | male | 18 | 200 | 200 | 技术 | | 5 | liwenzhou | male | 18 | 200 | 200 | 技术 | | 2 | alex | female | 48 | 201 | 201 | 人力资源 | | 3 | wupeiqi | male | 38 | 201 | 201 | 人力资源 | | 4 | yuanhao | female | 28 | 202 | 202 | 销售 | | 6 | jingliyang | female | 18 | 204 | NULL | NULL | | NULL | NULL | NULL | NULL | NULL | 203 | 运营 | +------+------------+--------+------+--------+------+--------------+
三 符合条件连接查询
#示例1:以内连接的方式查询employee和department表,并且employee表中的age字段值必须大于25,即找出公司所有部门中年龄大于25岁的员工 select employee.name,employee.age from employee,department where employee.dep_id = department.id and age > 25; #示例2:以内连接的方式查询employee和department表,并且以age字段的升序方式显示 select employee.id,employee.name,employee.age,department.name from employee,department where employee.dep_id = department.id and age > 25 order by age asc;
四 子查询
#1:子查询是将一个查询语句嵌套在另一个查询语句中。 #2:内层查询语句的查询结果,可以为外层查询语句提供查询条件。 #3:子查询中可以包含:IN、NOT IN、ANY、ALL、EXISTS 和 NOT EXISTS等关键字 #4:还可以包含比较运算符:= 、 !=、> 、<等
1 带IN关键字的子查询
#查询employee表,但dep_id必须在department表中出现过 select * from employee where dep_id in (select id from department);
2 带比较运算符的子查询
#比较运算符:=、!=、>、>=、<、<=、<> #查询平均年龄在25岁以上的部门名 select id,name from department where id in (select dep_id from employee group by dep_id having avg(age) > 25); #查看技术部员工姓名 select name from employee where dep_id in (select id from department where name='技术'); #查看不足1人的部门名 select name from department where id in (select dep_id from employee group by dep_id having count(id) <=1);
3 带EXISTS关键字的子查询
EXISTS关字键字表示存在。在使用EXISTS关键字时,内层查询语句不返回查询的记录。
而是返回一个真假值。True或False
当返回True时,外层查询语句将进行查询;当返回值为False时,外层查询语句不进行查询
#department表中存在dept_id=203,Ture mysql> select * from employee -> where exists -> (select id from department where id=200); +----+------------+--------+------+--------+ | id | name | sex | age | dep_id | +----+------------+--------+------+--------+ | 1 | egon | male | 18 | 200 | | 2 | alex | female | 48 | 201 | | 3 | wupeiqi | male | 38 | 201 | | 4 | yuanhao | female | 28 | 202 | | 5 | liwenzhou | male | 18 | 200 | | 6 | jingliyang | female | 18 | 204 | +----+------------+--------+------+--------+ #department表中存在dept_id=205,False mysql> select * from employee -> where exists -> (select id from department where id=204); Empty set (0.00 sec)
五 综合练习
init.sql文件内容
View Code
从init.sql文件中导入数据
#准备表、记录 mysql> create database db1; mysql> use db1; mysql> source /root/init.sql
!!!重中之重:练习之前务必搞清楚sql逻辑查询语句的执行顺序
链接:http://www.cnblogs.com/linhaifeng/articles/7372774.html
1、查询所有的课程的名称以及对应的任课老师姓名 2、查询学生表中男女生各有多少人 3、查询物理成绩等于100的学生的姓名 4、查询平均成绩大于八十分的同学的姓名和平均成绩 5、查询所有学生的学号,姓名,选课数,总成绩 6、 查询姓李老师的个数 7、 查询没有报李平老师课的学生姓名 8、 查询物理课程比生物课程高的学生的学号 9、 查询没有同时选修物理课程和体育课程的学生姓名 10、查询挂科超过两门(包括两门)的学生姓名和班级 、查询选修了所有课程的学生姓名 12、查询李平老师教的课程的所有成绩记录 13、查询全部学生都选修了的课程号和课程名 14、查询每门课程被选修的次数 15、查询之选修了一门课程的学生姓名和学号 16、查询所有学生考出的成绩并按从高到低排序(成绩去重) 17、查询平均成绩大于85的学生姓名和平均成绩 18、查询生物成绩不及格的学生姓名和对应生物分数 19、查询在所有选修了李平老师课程的学生中,这些课程(李平老师的课程,不是所有课程)平均成绩最高的学生姓名 20、查询每门课程成绩最好的前两名学生姓名 21、查询不同课程但成绩相同的学号,课程号,成绩 22、查询没学过“叶平”老师课程的学生姓名以及选修的课程名称; 23、查询所有选修了学号为1的同学选修过的一门或者多门课程的同学学号和姓名; 24、任课最多的老师中学生单科成绩最高的学生姓名
1、查询所有的课程的名称以及对应的任课老师姓名 SELECT c.cname,t.tname FROM course c LEFT JOIN teacher t ON c.teacher_id=t.tid 2、查询学生表中男女生各有多少人 SELECT gender,COUNT(sid) FROM student GROUP BY gender 3、查询物理成绩等于100的学生的姓名 SELECT stu.sname FROM student stu LEFT JOIN score s ON s.student_id=stu.sid LEFT JOIN course c ON c.cid=s.course_id WHERE s.num=100 AND c.cname="物理" SELECT sname FROM student WHERE sid IN(SELECT student_id FROM score WHERE num=100 AND course_id =(SELECT cid FROM course WHERE cname="物理")) 4、查询平均成绩大于八十分的同学的姓名和平均成绩 SELECT s.sname, 平均成绩 FROM student s RIGHT JOIN (SELECT student_id ,AVG(num) 平均成绩 FROM score GROUP BY student_id HAVING AVG(num)>80 )AS sc ON s.sid=sc.student_id 5、查询所有学生的学号,姓名,选课数,总成绩 SELECT s.sid 学号,s.sname 姓名,选课数,总成绩 FROM student s RIGHT JOIN (SELECT student_id,COUNT(course_id) 选课数,SUM(num) 总成绩 FROM score GROUP BY student_id)AS sc ON s.sid=sc.student_id 6、 查询姓李老师的个数 SELECT COUNT(tid) FROM teacher WHERE tname LIKE "李%" 7、 查询没有报李平老师课的学生姓名 SELECT sname FROM student WHERE sid NOT IN (SELECT student_id FROM score WHERE course_id IN (SELECT cid FROM course WHERE teacher_id =(SELECT tid FROM teacher WHERE tname="李平老师"))) SELECT sname FROM student WHERE sid NOT IN ( SELECT student_id FROM score s LEFT JOIN course c ON c.cid=s.course_id WHERE c.cid IN( SELECT cid FROM course c INNER JOIN teacher t ON t.tid=c.teacher_id WHERE t.tname="李平老师" ) ) 8、查询物理课程比生物课程高的学生的学号 SELECT * FROM (SELECT student_id 学生号, num 成绩,cname 课程 FROM score LEFT JOIN course ON course_id=score.course_id WHERE cname="物理")AS wl INNER JOIN (SELECT student_id 学生号, num 成绩,cname 课程 FROM score LEFT JOIN course ON course_id=score.course_id WHERE cname="生物")AS sw ON wl.成绩>sw.成绩 SELECT t1.student_id FROM (SELECT student_id,num FROM score s INNER JOIN course c ON c.cid=s.course_id WHERE c.cname="物理")AS t1 JOIN (SELECT student_id,num FROM score s INNER JOIN course c ON c.cid=s.course_id WHERE c.cname="生物")AS t2 ON t1.student_id=t2.student_id WHERE t1.num>t2.num 9、查询没有同时选修物理课程和体育课程的学生姓名 SELECT sname FROM student WHERE sid NOT IN( SELECT student_id FROM score WHERE course_id IN (SELECT cid FROM course WHERE cname IN ("物理","生物"))GROUP BY student_id HAVING COUNT(course_id)=2 ) 10、查询挂科超过两门(包括两门)的学生姓名和班级 SELECT sname,cl.caption FROM student stu ,class cl WHERE stu.sid IN( SELECT s.student_id FROM score s LEFT JOIN course c ON s.course_id = c.cid WHERE num<60 GROUP BY student_id HAVING COUNT(sid)>=2 )AND stu.class_id=cl.cid SELECT sname,caption FROM student stu ,class cl WHERE stu.sid IN( SELECT student_id FROM score WHERE num<60 GROUP BY student_id HAVING COUNT(sid)>=2) AND stu.class_id=cl.cid SELECT t2.sname ,cl.caption FROM ( SELECT sname ,class_id FROM student stu INNER JOIN ( SELECT student_id FROM score WHERE num<60 GROUP BY student_id HAVING COUNT(course_id)>=2) AS t1 ON stu.sid=t1.student_id )AS t2 INNER JOIN class cl ON cl.cid=t2.class_id 11 、查询选修了所有课程的学生姓名 SELECT s.sid, s.sname FROM student s WHERE s.sid IN( SELECT s.student_id FROM score s GROUP BY student_id HAVING COUNT(s.sid)=(SELECT COUNT(cid) FROM course) ) 12、查询李平老师教的课程的所有成绩记录 SELECT s.num ,c.cname FROM score s INNER JOIN course c ON s.course_id=c.cid WHERE c.cid IN (SELECT c.cid FROM course c INNER JOIN teacher t ON c.teacher_id=t.tid WHERE tname="李平老师") SELECT s.num ,c.cname FROM score s LEFT JOIN course c ON c.cid=s.course_id LEFT JOIN teacher t ON t.tid=c.teacher_id WHERE t.tname="李平老师" 13、查询全部学生都选修了的课程号和课程名 SELECT cid,cname FROM course WHERE cid IN( SELECT course_id FROM score GROUP BY course_id HAVING COUNT(sid)=( SELECT COUNT(sid) FROM student ) ) SELECT c.cid,c.cname FROM course c WHERE c.cid IN( SELECT course_id FROM score GROUP BY course_id HAVING COUNT(sid)=(SELECT COUNT(sid) FROM student) ) 14、查询每门课程被选修的次数 SELECT c.cname ,COUNT(sid) FROM course c LEFT JOIN score s ON s.course_id =c.cid GROUP BY s.course_id 15、查询只选修了一门课程的学生姓名和学号 SELECT sid,sname FROM student WHERE sid IN(SELECT student_id FROM score GROUP BY student_id HAVING COUNT(sid)=1) 16、查询所有学生考出的成绩并按从高到低排序(成绩去重) 查询每个考生对应的成绩 SELECT stu.sname,s.num FROM student stu LEFT JOIN score s ON s.student_id=stu.sid ORDER BY s.num DESC 查询所有学生考出的成绩并按从高到低排序(成绩去重) SELECT DISTINCT num FROM score ORDER BY num DESC 17查询平均成绩大于85的学生姓名和平均成绩 SELECT stu.sname 姓名,AVG(s.num )平均成绩 FROM student stu INNER JOIN score s ON stu.sid =s.student_id GROUP BY s.student_id HAVING AVG(num)>85 18、查询生物成绩不及格的学生姓名和对应生物分数 SELECT stu.sname 姓名,s.num 生物成绩 FROM score s LEFT JOIN student stu ON stu.sid=s.student_id LEFT JOIN course c ON s.course_id=c.cid WHERE c.cname="生物" AND s.num<60 19、查询在所有选修了李平老师课程的学生中,这些课程(李平老师的课程,不是所有课程) 平均成绩最高的学生姓名 SELECT stu.sname FROM score s LEFT JOIN student stu ON s.student_id=stu.sid LEFT JOIN course c ON c.cid=s.course_id WHERE c.cid IN (SELECT c.cid FROM course c LEFT JOIN teacher t ON c.teacher_id =t.tid WHERE t.tname="李平老师" ) GROUP BY student_id ORDER BY AVG(s.num) DESC LIMIT 1 20、查询每门课程成绩最好的前两名学生姓名 SELECT s.sid,s.course_id,s.num,ss.first_num,ss.second_num FROM score s LEFT JOIN ( SELECT sid, (SELECT num FROM score AS s2 WHERE s2.course_id = s1.course_id ORDER BY num DESC LIMIT 0,1) AS first_num, (SELECT num FROM score AS s2 WHERE s2.course_id = s1.course_id ORDER BY num DESC LIMIT 1,1) AS second_num FROM score AS s1 ) AS ss ON s.sid =ss.sid WHERE s.num <= ss.first_num AND s.num >= ss.second_num 21、查询不同课程但成绩相同的学号,课程号,成绩 SELECT s1.student_id, s1.course_id, s1.num, s2.student_id , s2.course_id,s2.num FROM score AS s1, score AS s2 WHERE s1.num = s2.num AND s1.course_id != s2.course_id AND s1.student_id!= s2.student_id; 22、查询没学过“叶平”老师课程的学生姓名以及选修的课程名称; SELECT stu.sname 姓名 FROM student stu WHERE stu.sid NOT IN ( SELECT student_id FROM score WHERE course_id IN( SELECT cid FROM course WHERE teacher_id=( SELECT tid FROM teacher WHERE tname="李平老师" ) ) ) 23、查询所有选修了学号为1的同学选修过的一门或者多门课程的同学学号和姓名; SELECT DISTINCT stu.sid, stu.sname FROM student stu LEFT JOIN score s ON s.student_id=stu.sid WHERE s.course_id IN( SELECT course_id FROM score WHERE student_id =1) SELECT stu.sid,stu.sname FROM student stu WHERE stu.sid IN( SELECT student_id FROM score WHERE course_id IN (SELECT course_id FROM score WHERE student_id =1) ) 24、任课最多的老师中学生单科成绩最高的学生姓名 SELECT stu.sname FROM score s LEFT JOIN student stu ON stu.sid=s.student_id LEFT JOIN course c ON s.course_id =c.cid WHERE c.teacher_id =( SELECT teacher_id FROM course GROUP BY teacher_id ORDER BY COUNT(cid) DESC LIMIT 1) GROUP BY s.student_id ORDER BY AVG(s.num) DESC LIMIT 2 SELECT stu.sname FROM student stu LEFT JOIN score s ON s.student_id =stu.sid LEFT JOIN course c ON c.cid=s.course_id WHERE cid IN( SELECT cid FROM course WHERE teacher_id =(SELECT teacher_id FROM course GROUP BY teacher_id ORDER BY COUNT(cid) DESC LIMIT 1))GROUP BY s.student_id ORDER BY AVG(s.num) DESC LIMIT 2